The formula for distance is equal to:
d = v * t
where d is distance, v is velocity or speed, and t is
time
Since the distance travelled by the two airplane is
similar, therefore we can create the initial equation:
v1 * t1 = v2 * t2
We know that v1 = 496, and v2 = 558 so:
496 t1 = 558 t2
or
x = 558 t2 / 496
We also know that airplane 1 travelled 30 minutes (0.5
hours) earlier than airplane 2, therefore:
x = t2 + 0.5
Hence,
496 (t2 + 0.5) = 558 t2
496 t2 + 248 = 558 t2
t2 = 4 hours
x = t2 + 0.5 = 4 + 0.5
x = 4.5 hours
So the equation is:
x = 558 t2 / 496
And the first plane travelled:
x = 4.5 hours
Answer:
$0.09.
Step-by-step explanation:
2.99/33
= $0.0906
Answer:
Step-by-step explanation:
There are 125 members.
89 of them preferred pizza and 23 of 89 preferred punch, so 89-23=66 preferred only pizza.
52 members preferred punch, 23 of them preferred both pizza and punch, so 52-23=29 preferred only punch.
Now,
66 members preferred only pizza,
23 members preferred both,
29 members preferred only punch,
125-66-23-29=7 members did not prefer both
The two-way table is
A, the interquartile range is 10, does not fit.
The interquartile range is found by subtracting the upper quartile and the lower quartile; in a box-and-whisker plot these are the outer edges of the box. In this case, they are 40 and 20; 40-20 = 20, not 10.
