Answer:
x=3, y=4
Step-by-step explanation:
hope this helps!
pls mark brainliest
Step-by-step explanation:
Let the height above which the ball is released be H
This problem can be tackled using geometric progression.
The nth term of a Geometric progression is given by the above, where n is the term index, a is the first term and the sum for such a progression up to the Nth term is
To find the total distance travel one has to sum over up to n=3. But there is little subtle point here. For the first bounce ( n=1 ), the ball has only travel H and not 2H. For subsequent bounces ( n=2,3,4,5...... ), the distance travel is 2×(3/4)n×H
a=2H..........r=3/4
However we have to subtract H because up to the first bounce, the ball only travel H instead of 2H
Therefore the total distance travel up to the Nth bounce is
For N=3 one obtains
D=3.625H
Answer:
Step-by-step explanation:
Given
Required
The domain and range
A function is represented as:
Where
domain
range
So, we have:
Answer:
<em>733 x 60 = </em><em>43,980.</em>
Step-by-step explanation:
Another way to do this equation is by <em>adding 733 by itself 60 times.</em>
