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3 years ago

Find AT AND RC. 80 points

Mathematics

2 answers:

stealth61 [152]3 years ago

6 0

Answer:

AT=6, RC=5

Step-by-step explanation:

Perpendicular bisector intersect at T that is the circumcenter.

since RT is a bisector or AC and AR=5 then RC=5

Circumcenter is equidistant from the vercices of the triangle so

AT≅BT≅CT

but CT is given to be CT=6 so AT=6

Vsevolod [243]3 years ago

6 0

Answer:

AT=6, RC=5

Step-by-step explanation:

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Komok [63]

Answer:

Step-by-step explanation:

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3 years ago

6x2 - 5x - 4 is equivalent to:

Sophie [7]

Answer:

(2x + 1) (3x - 4)

Step-by-step explanation:

Solution:

6x² - 5x - 4
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2 years ago

Please help ASAP! Thanks! For the figures below, assume they are made of semicircles, quarter circles and squares. For each shap

bazaltina [42]

Answer:

Part 1) $A=36(\pi-2)\ cm^2$

Part 2) $P=6(\pi+2\sqrt{2})\ cm$

Step-by-step explanation:

Part 1) Find the area

we know that

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$A=\frac{1}{4}\pi r^{2}-\frac{1}{2}(b)(h)$

we have that the base and the height of triangle is equal to the radius of the circle

$r=12\ cm\\b=12\ cm\\h=12\ cm$

substitute

$A=\frac{1}{4}\pi (12)^{2}-\frac{1}{2}(12)(12)$

$A=(36\pi-72)\ cm^2$

simplify

Factor 36

$A=36(\pi-2)\ cm^2$

Part 2) Find the perimeter

The perimeter of the figure is equal to the circumference of a quarter of circle plus the hypotenuse of the right triangle

The circumference of a quarter of circle is equal to

$C=\frac{1}{4}(2\pi r)=\frac{1}{2}\pi r$

substitute the given values

$C=\frac{1}{2}\pi (12)$

$C=6\pi\ cm$

The hypotenuse of right triangle is equal to (applying the Pythagorean Theorem)

$AC=\sqrt{12^2+12^2}$

$AC=\sqrt{288}\ cm$

simplify

$AC=12\sqrt{2}\ cm$

Find the perimeter

$P=(6\pi+12\sqrt{2})\ cm$

simplify

Factor 6

$P=6(\pi+2\sqrt{2})\ cm$

6 0

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Iteru [2.4K]

Answer:

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Step-by-step explanation:

This problem bothers on the density of substances

Given data

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notka56 [123]

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