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3 years ago

Help please! Thank you!

Mathematics

2 answers:

dimaraw [331]3 years ago

8 0

Answer:

slope: -1/5

y-intercept: -6

Step-by-step explanation:

In an equation of the form

y = mx + b,

m is the slope, and b is the y-intercept.

You have

y = -1/5 x - 6,

so the slope is m which is -1/5, and the y-intercept is -6.

Alex17521 [72]3 years ago

8 0

The slope is 1/5 and the y intercepts is -6

Glad to help

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5 Points | Which of the following are remote interior angles of 6? Check all that apply.

aniked [119]

Answer: 1 and 3

Step-by-step explanation:

I had the same question on my test the other day hope this helped.

4 0

3 years ago

If two points known on the line AB in the coordinate plane is (7,15) and (18,42), calculate the following..

Ksju [112]

Answer:

Slope = 27/11
AB = 29.15 u

Step-by-step explanation:

Given :-

Two points are given to us .
The points are A(7,15) and B(18,42)

To Find :-

The slope of the line .
The length of line AB .

We can find the slope of the line passing through the points $( x_1,y_1)$ and $( x_2,y_2)$ as ,

$\implies m = \dfrac{ y_2-y_1}{x_2-x_{1}}$

Plug in the respective values ,

$\implies m = \dfrac{ 42-15}{18-7} \\\\\implies \boxed{ m = \dfrac{ 27}{11 }}$

Hence the slope of the line is 27/11 .

$\rule{200}2$

Finding the length of AB :-

We can find the distance between them by using the Distance Formula .

$\implies Distance =\sqrt{ (x_2-x_1)^2+(y_2-y_1)^2} \\\\\implies Distance =\sqrt{ (18-7)^2+(42-15)^2 } \\\\\implies Distance =\sqrt{ 11^2 + 27^2 } \\\\\implies Distance =\sqrt{ 121 + 729 } \\\\\implies Distance = \sqrt{ 850} \\\\\implies \boxed{ Distance = 29.15 \ units }$

Hence the length of AB is 29.15 units .

5 0

3 years ago

A clock is positioned on an auditorium wall with its center 9 ft above the floor. The second hand on the clock is 10 inches long

oee [108]

Answer:

B : y=5/6cos(pi/30x)+9

Step-by-step explanation:

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3 years ago

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PLEASE HELP ASAP! 30 points!

rusak2 [61]

200=2m+18
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3 years ago

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Simplify: cos2x-cos4 all over sin2x + sin 4x

GrogVix [38]

Answer:

$\frac{\cos\left(2x\right)-\cos\left(4x\right)}{\sin\left(2x\right)+\sin\left(4x\right)}=\tan\left(x\right)$

Step-by-step explanation:

$\frac{\cos\left(2x\right)-\cos\left(4x\right)}{\sin\left(2x\right)+\sin\left(4x\right)}$

Apply formula:

$\cos\left(A\right)-\cos\left(B\right)=-2\cdot\sin\left(\frac{A+B}{2}\right)\cdot\sin\left(\frac{A-B}{2}\right)$ and

$\sin\left(A\right)+\sin\left(B\right)=2\cdot\sin\left(\frac{A+B}{2}\right)\cdot\sin\left(\frac{A-B}{2}\right)$

We get:

$=\frac{-2\cdot\sin\left(\frac{2x+4x}{2}\right)\cdot\sin\left(\frac{2x-4x}{2}\right)}{2\cdot\sin\left(\frac{2x+4x}{2}\right)\cdot\cos\left(\frac{2x-4x}{2}\right)}$