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victus00 [196]
3 years ago
6

Find two consecutive odd integers whose sum is 111

Mathematics
2 answers:
notka56 [123]3 years ago
8 0
The two odd numbers who’s sum is 111 are 53.5 and 57.5.
VARVARA [1.3K]3 years ago
7 0

Answer:

54.5 and 56.5

Step-by-step explanation:

To solve this, we need to know the meaning of the term 'consecutive odd integers'

Consecutive odd integers are odd odd integers which follow each other in the pattern such as; 1, 3, 5, 7,9,11,13,15------etc

This implies they take the form n, n+2, n+4, n+6, n+8, n+10--------etc where n is an odd number.

Haven gotten the above definition, we will now proceed to solve the question.

we are ask to find the two consecutive odd numbers whose sum is 111

let the two numbers be n and n+2

n + n+2 =111

2n + 2 = 111

subtract 2 from both-side of the equation

2n + 2 - 2 = 111 -2

2n = 109

Divide both-side of the equation by 2

\frac{2n}{2}   =  \frac{109}{2}

(at the left-hand side of the equation 2 will cancel-out 2, leaving us with just n and on the right-hand side of the equation 109 will be divided by 2)

n = 54.5

The first number is n=54.5

The second number is n+2 = 54.5 + 2 =56.5

Therefore, the two consecutive numbers whose sum is 111 is 54.5 and 56.5

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Answer:

We can claim with 95% confidence that the proportion of executives that prefer trucks is between 19.2% and 32.8%.

Step-by-step explanation:

We have a sample of executives, of size n=160, and the proportion that prefer trucks is 26%.

We have to calculate a 95% confidence interval for the proportion.

The sample proportion is p=0.26.

 

The standard error of the proportion is:

\sigma_p=\sqrt{\dfrac{p(1-p)}{n}}=\sqrt{\dfrac{0.26*0.74}{160}}\\\\\\ \sigma_p=\sqrt{0.0012}=0.0347

The critical z-value for a 95% confidence interval is z=1.96.

The margin of error (MOE) can be calculated as:

MOE=z\cdot \sigma_p=1.96 \cdot 0.0347=0.068

Then, the lower and upper bounds of the confidence interval are:

LL=p-z \cdot \sigma_p = 0.26-0.068=0.192\\\\UL=p+z \cdot \sigma_p = 0.26+0.068=0.328

The 95% confidence interval for the population proportion is (0.192, 0.328).

We can claim with 95% confidence that the proportion of executives that prefer trucks is between 19.2% and 32.8%.

3 0
3 years ago
1¾-2¼<br>pls give me formula​
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Answer:

=7/4 - 9/4 = -2/4

Step-by-step explanation:

1¾ = (4×1+3)/4

2¼ = (4×2+1)/4

5 0
3 years ago
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Answer:

A fish processing company in Charlotteville processes three types of products: Type A, Type B, and Type C. Its operations involve three basic activities: cleaning, cutting and packaging.

Step-by-step explanation:

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3 years ago
A researcher was testing the number of popcorn kernels that popped out of a mini bag of 100 kernels after being cooked for the s
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Answer:

The percentage of the bag that should have popped 96 kernels or more is 2.1%.

Step-by-step explanation:

The random variable <em>X</em> can be defined as the number of popcorn kernels that popped out of a mini bag.

The mean is, <em>μ</em> = 72 and the standard deviation is, <em>σ</em> = 12.

Assume that the population of the number of popcorn kernels that popped out of a mini bag follows a Normal distribution.

Compute the probability that a bag popped 96 kernels or more as follows:

Apply continuity correction:

P( X\geq 96)=P( X>96+0.50)

                 =P( X>96.50)\\=P(\frac{X-\mu}{\sigma}>\frac{96.50-72}{12})\\=P(Z>2.04)\\=1-P(Z

*Use a <em>z</em>-table.

The probability that a bag popped 96 kernels or more is 0.021.

The percentage is, 0.021 × 100 = 2.1%.

Thus, the percentage of the bag that should have popped 96 kernels or more is 2.1%.

3 0
3 years ago
The perimeter of a rectangle swimming pool is a 114 ft. The width is 7ft more than the lenth. Find lenght and width
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Answer:

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Step-by-step explanation:

First: 7x2=14

Then: 114-14=100

Hope this helps

-Mercury

7 0
3 years ago
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