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Mila [183]
3 years ago
9

If the sum of the total mining costs for student 1 and student 2 is $40, what is the cost of equipment for student 2?

Mathematics
1 answer:
Andreyy893 years ago
4 0
If they're both equal $20 but there is many different ways to answer this like 19 plus 21
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Point G is the centroid of triangle abc use the information to find the value of x.
ioda
<span>
2. FG= x +8 and AF = 9x - 6</span>
5 0
3 years ago
What is the solution to this inequality?
solong [7]

Answer: x>−4

Step-by-step explanation:

Let's solve your inequality step-by-step.

6x−5>−29

Step 1: Add 5 to both sides.

6x−5+5>−29+5

6x>−24

Step 2: Divide both sides by 6.

6x/6>-24/6

<h3>x>-4</h3>
7 0
3 years ago
Please Help I'm not really good at math
UkoKoshka [18]

The true statements about the triangles RST and DEF are: (a), (d) and (e)

<h3>How to determine the true statements?</h3>

The statement ΔRST ≅ ΔDEF means that the triangles RST and DEF are congruent.

This above implies that:

  • The triangles can be mapped onto each other by rigid transformations such as reflection, translation and rotation
  • The transformation does not include dilation
  • Corresponding sides are congruent

The above means that the possible true statements are: (a), (d) and (e)

Read more about transformation at:

brainly.com/question/4289712

#SPJ1

3 0
2 years ago
What are the factors of 2x + 3x - 54? Select two options
tiny-mole [99]

Answer:

The answer: The factors are (2x-9) and (x+6).

The Problem:

Factor 2x^2+3x-54

Step-by-step explanation:

So I'm going to do trial factors using the choices to aid me.

Factored form for this problem if it exist will be in the form:

(mx+n)(kx+p).

In general this is what it would look like if we factored any quadratic in terms of x (given the quadratic is not prime but technically you could factor even over the complex numbers).

Let's look at:

(mx+n)(kx+p)

We want to choose k \text{ and } m such that when you multiply them you get 2.  Well those would have to be 2 and 1.

(2x+n)(x+p)

we want to choose n \text{ and } p such that when you multiply them you get -54. Based on the choices we want to get with -9 and 6, or 9 and -6. We don't know the order we want to choose it in either.

For example which of these would work:

(2x-6)(x+9)

(2x+6)(x-9)

(2x-9)(x+6)

(2x+9)(x-6)

We are going to consider only the outer and inner of FOIL since we already know the first times the first is 2x^2 and the last times the last is -54.

Let's test the first one:

(2x-6)(x+9)

Outer:  2x(9)=18x

Inner: -6(x)=-6x

------------------------ADD!

18x-6x=12x

The first choice did not give us the middle term 3x.

Trying the second one would give us the opposite since they are in the same form as previous just the + and - are switched.

Let's look at the third one:

(2x-9)(x+6)

Outer: 2x(6)=12x

Inner: -9(x)=-9x

--------------------------ADD!

12x-9x=3x

This is the winner.

The answer: The factors are (2x-9) and (x+6).

7 0
3 years ago
Read 2 more answers
A study was designed to compare the attitudes of two groups of nursing students towards computers. Group 1 had previously taken
Leviafan [203]

Answer:

a. H0:μ1≥μ2

Ha:μ1<μ2

b. t=-3.076

c. Rejection region=[tcalculated<−1.717]

Reject H0

Step-by-step explanation:

a)

As the score for group 1 is lower than group 2,

Null hypothesis: H0:μ1≥μ2

Alternative hypothesis: H1:μ1<μ2

b) t test statistic for equal variances

t=(xbar1-xbar2)-(μ1-μ2)/sqrt[{1/n1+1/n2}*{((n1-1)s1²+(n2-1)s2²)/n1+n2-2}

t=63.3-70.2/sqrt[{1/11+1/13}*{((11-1)3.7²+(13-1)6.6²)/11+13-2}

t=-6.9/sqrt[{0.091+0.077}{136.9+522.72/22}]

t=-3.076

c. α=0.05, df=22

t(0.05,22)=-1.717

The rejection region is t calculated<t critical value

t<-1.717

We can see that the calculated value of t-statistic falls in rejection region and so we reject the null hypothesis at 5% significance level.

7 0
3 years ago
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