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Mila [183]
3 years ago
9

If the sum of the total mining costs for student 1 and student 2 is $40, what is the cost of equipment for student 2?

Mathematics
1 answer:
Andreyy893 years ago
4 0
If they're both equal $20 but there is many different ways to answer this like 19 plus 21
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a square field has a side 150 m long .There is a road 5 m wide all around the park outside it .Find the cost of constructing the
alisha [4.7K]

Answer:

Cost to construct the road = 775000 rupees

Step-by-step explanation:

Square field has a side = 150 m

Area of the field = (Side)²

                           = (150)²

                           = 22500 m²

Length of the park with road around the field = 150 + 2×(width of the road)

                                                                            = 150 + (2×5)

                                                                            = 160 m

Similarly, width of the park with road around the field = 160 m

Area of the park with road = (Side)²

                                            = (160)²

                                            = 25600 m²

Area of road = Area of the park with road - Area of the park

                     = 25600 - 22500

                     = 3100 m²

Since, cost of constructing the road = 250 rupees per square meter

Cost to construct the road with the given area = 250 × 3100

                                                                              = 775000 rupees

6 0
3 years ago
Micah can do 75 push up in 3 minutes Edward Lowe can do 130 push-ups in 5 minutes are these rates equivalent
IrinaK [193]
No because Edward can do 26 push-ups per minute while Micah can only do 25 push-ups per minute
6 0
4 years ago
What is the answer to this ? 6/2(1+2) ?
Andru [333]

Your answer is 9. Hope this helps, if not, please comment below!

5 0
3 years ago
Which statement explains how to correct the error that was made?
Svetradugi [14.3K]

Answer:

I believe that this is the best answer mark brainliest if it is

Step-by-step explanation:

The square root property should have been applied to both complete sides of the equation instead of to select

variables.

4 0
3 years ago
Chloe is painting on a stretched canvas that has an area of 108 square inches. The length of the canvas is 12 inches. The width
Stolb23 [73]

Answer: Width of canvas = 9 inches

Area left for painting after painting the border = 70 square inches.

Explanation :

Since we have given that

Area of painting = 108 square inches

Length of canvas = 12 inches

As we know that

\text{Area of rectangle} = length\times breadth

108=12\times breadth\\\\\frac{108}{12}=breadth\\\\9=breadth

So, breadth of canvas = 9 inches .

Now, Chloe paints a 1 inch wide blue border on the canvas.

\text{So, remaining length left for painting after painting the border} = 9-1-1=9-2=7\text{ inches}

\text{ Remaining breadth left for painting after painting the border }= 12-1-1=12-2= 10\text{ inches}

\text{So , area of remaining portion }= length\times breadth \\\\ \text{ area of remaining portion }=7\times 10\\\\\text{ area of remaining portion }=70 \text{ square inches}

Hence, remaining area = 70 square inches .

6 0
3 years ago
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