find me the volume of a box with the length of 5 Centimeters a width of 5 centimeters and a height of 10 centimeters

Help? I forgot how to do this lol I have really bad memory

pashok25 [27]

$\dfrac{2}{3} \times \dfrac{3}{4} \times \dfrac{1}{2}$

Cancel out 2, the common factor for the numerator and denominator:

$= \dfrac{1}{3} \times \dfrac{3}{4} \times \dfrac{1}{1}$

Cancel out 3, the common factor for the numerator and denominator:

$= \dfrac{1}{1} \times \dfrac{1}{4} \times \dfrac{1}{1}$

Combine into single fraction:

$= \dfrac{1 \times 1 \times 1}{1 \times 4 \times 1 } = \dfrac{1}{4}$

$\bf \text {Answer = } \dfrac{1}{4}$

8 0

3 years ago

Find the exact solution to the equation. <img src="https://tex.z-dn.net/?f=log_%7B4%7D%20x%3D2" id="TexFormula1" title="log_{4}

Ilia_Sergeevich [38]

Answer:

x = 16

Step-by-step explanation:

log₄ˣ = 2

x = 4²

x = 16

8 0

3 years ago

Consider the probability that fewer than 26 out of 107 cell phone calls will be disconnected. Assume the probability that a give

anyanavicka [17]

Answer:

We assume the condition of independence satisifed.

We need to check the following conditions in order to use the normal approximation.

$np=107*0.98=104.86 \geq 10$

$n(1-p)=107*(1-0.98)=2.14 < 10$

So we see that we satisfy the first condition, but the second no so then we can't apply the approximation for this case, since we need both conditions at the same time in order to use the normal approximation.

Step-by-step explanation:

Previous concepts

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".

Let X the random variable of interest, on this case we now that:

$X \sim Binom(n=107, p=0.98)$

The probability mass function for the Binomial distribution is given as:

$P(X)=(nCx)(p)^x (1-p)^{n-x}$

Where (nCx) means combinatory and it's given by this formula:

$nCx=\frac{n!}{(n-x)! x!}$

Solution to the problem

We assume the condition of independence satisifed.

We need to check the following conditions in order to use the normal approximation.

$np=107*0.98=104.86 \geq 10$

$n(1-p)=107*(1-0.98)=2.14 < 10$

So we see that we satisfy the first condition, but the second no so then we can't apply the approximation for this case, since we need both conditions at the same time in order to use the normal approximation.

4 0

3 years ago

the pressure, p. of a gas varies inversely with its volume, v. Pressure is measured in units of Pa. Suppose that a particular am

LekaFEV [45]

I think I know how to do it

Your equation is:

P₁V₁ = P₂V₂

You Know:

Initial:

P₁ = 84 Pa

V₁ = 336 L

New:

P₂ = ?

V₂ = 216L

Plug this into the equation:

P₁V₁ = P₂V₂

(84 Pa)(336 L) = P₂(216 L) Divide 216 on both sides

$\frac{(84Pa)(336L)}{216L}=\frac{(P_{2})(216L)}{216L}$

130.6666666 = P₂

(if your doing significant figures, you have 2 sig figs)

130 Pa = P₂

6 0

3 years ago

Match each trig function to a ratio. cos (A) =

soldi70 [24.7K]

Answer:

Cos A = x/z

Step-by-step explanation:

You need to memorize the definitions of all the trig functions and then these types of problems become easy! OK?

Cos = adjacent side/hypotenuse

Cos A = x/z

7 0

3 years ago