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2 years ago

ILL GIVE YOU BRAINLIEST!! Solve `x^{2}-5x+6=0`

Mathematics

2 answers:

kramer2 years ago

5 0

Answer:

Factoring

Step-by-step explanation:

$x^2-5x+6=0$

$x^2-2x-3x+6=0$

$x(x-2)-3(x-2)$

$(x-3)(x-2)=0$

$x=2$ and $x=3$

Serjik [45]2 years ago

4 0

I hope this help!

(Take note that this explanation is not written by me. The creator of the equation is by someone else.)

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Let U= U= Universal set ={0, 1, 2, 3, 4, 5, 6, 7, 8, 9}={0, 1, 2, 3, 4, 5, 6, 7, 8, 9} , A={1, 3, 4, 5, 7, 9} A={1, 3, 4, 5, 7,

blagie [28]

Answer:

a) $A' = [0,2,6,8]$

b) $(AUB)' = [0,2,6]$

c) $(AUB')' = [9]$

d) A∩B′ $= [3,5,9]$

Step-by-step explanation:

Assuming this problem: "Let U= U= Universal set ={0, 1, 2, 3, 4, 5, 6, 7, 8, 9} , A={1, 3, 4, 5, 7, 9} , and B={1, 4, 7, 8} . List the elemetns of the following sets in the increasing order: a) A′= b) (A∪B)′={ , , }} c) (A∪B′)′={ }} d) A∩B′={ , , }}"

Part a

For this case we just need to find the elements in the universal set that are not in A. And we see that:

$A' = [0,2,6,8]$

And that represent the complement for A

Part b

For this case we need to find first the Union AUB who are the elements on A or B without repetition and we got:

$AUB = [1,3,4,5,7,8,9]$

And now the complement for (AUB)' are the elements that are not in AUB but are on the universal set and we got:

$(AUB)' = [0,2,6]$

Part c

For this case we need to find B' who are the elements on the universal set that are not in B

$B' = [0,2,3,5,6,9]$

Then we can find the union between AUB' and we got:

$AUB' = [0,1,2,3,4,5,6,7,9]$

And then the complment is just:

$(AUB')' = [9]$

Part d

For this case we just need to see the elements in common between A and B' and we got:

A∩B′ $= [3,5,9]$

6 0

4 years ago

The sixth-graders at Kate's school got to choose between a field trip to a museum and a field trip to a factory. 19 sixth-grader

amm1812

25% because 19+57= a total of 76 students and the percentage of 19 out of 76 is 25%.

19/76= 0.25

4 0

3 years ago

Find the value of 'x

viktelen [127]

Answer:

x = 16

Step-by-step explanation:

The sum of the angles of a triangle are 180

128+ 2x-3 +23 = 180

Combine like terms

2x+148=180

Subtract 148 from each side

2x+148 -148 = 180-148

2x = 32

Divide by 2

2x/2 = 32/2

x =16

5 0

3 years ago

If 2.22 moles of ammonia (NH3 ) decomposes according to the reaction shown, how many moles of hydrogen (H2 ) are formed? A. 1.11

egoroff_w [7]

Answer:

C. 3.33 moles

Step-by-step explanation:

Ammonia decomposes

$2NH_3\rightarrow N_2+3H_2$

We have to find the moles of hydrogen formed in 2.22 moles of ammonia.

From the reaction

2 moles of ammonia gives 3 moles of hydrogen

1 mole of ammonia produce hydrogen=3/2 moles

2.22 moles of ammonia produces hydrogen= $\frac{3}{2}\times 2.22$ moles

Number of moles of hydrogen formed by decomposition of 2.22 moles of ammonia

= $\frac{6.66}{2}=3.33$ moles

Hence, 3.33 moles of hydrogen are formed in 2.22 moles of ammonia.

Option C is true.

C. 3.33 moles

7 0

3 years ago

PLEASE HELP! I don't have a ton of points. but I really need help asap please!

uranmaximum [27]

Welllll i don’t really know I just need points so I hope you get a correct answerrrr!!!

5 0

3 years ago