Question

Math help ASAP!!!!!!!!!!

Answer 1

Answer:

(r+s) (x) = 4x+3

(r*s) (x) =  3x^2 +x-4

(r-s) (-1) =  -3

Step-by-step explanation:

r(x) = x-1

s(x) = 3x+4

(r+s) (x) =  x-1  + 3x+4

Combine like terms

           = 4x+3

(r*s) (x) = ( x-1)  ( 3x+4)

FOIL    

           = 3x^2 +4x-3x-4

           = 3x^2 +x-4

(r-s) (x) =  x-1  - (3x+4)

Distribute the minus sign

           =x-1-3x-4

           =-2x-5

Let x = -1

(r-s) (-1) =  -2(-1) -5

               2-5

                  -3

Answer 2

Answer:

$(r + s)(x)=4x+3$

$(r * s)(x)=3x^2+x-4$

$(r - s)(-1)=-3$

Step-by-step explanation:

We know that:

$r(x) =x-1\\s(x)=3x+4$

To find $(r + s) (x)$ we add the function $r (x)$ with the function $s (x)$

So

$(r + s)(x)=r(x)+s(x)$

$(r + s)(x)=x-1 + 3x+4$

$(r + s)(x)=4x+3$

To find $(r * s) (x)$ we multiply the function $r (x)$ with the function $s (x)$

So

$(r *s)(x)=r(x)*s(x)$

$(r * s)(x)=(x-1)(3x+4)$

Using the distributive property we have left that

$(r * s)(x)=3x^2+4x-3x-4$

$(r * s)(x)=3x^2+x-4$

To find $(r - s) (-1)$ we subtract the function $r (x)$ with the function $s (x)$  and then evaluate in (-1)

Then:

$(r - s)(-1)=r(x)-s(x)$

$(r - s)(-1)=x-1 - (3x+4)$

$(r - s)(-1)=x-1-3x-4$

$(r - s)(-1)=-2x-5$

$(r - s)(-1)=-2(-1)-5$

$(r - s)(-1)=2-5$

$(r - s)(-1)=-3$