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4 years ago

Are 5xyz and 10xy like terms ? pls answer!

Mathematics

2 answers:

DIA [1.3K]4 years ago

3 0

They are NOT like terms, as z multiplied to 5xy is not multiplied to 10xy in the same way

ASHA 777 [7]4 years ago

3 0

Answer:

Step-by-step explanation:

5xyz and 10xy are not like terms because 5xyz has a z and 10xy doesn't. Like terms always have the same variables.

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5. Makayla had $3.00 to spend at the school store. The prices are shown in

slavikrds [6]

$0.15 because I added all and multiplied them then subtracted it by $3.00

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3 years ago

Find the greatest common factor of 12a^3c and 15ab^3

storchak [24]

The greatest common factor of 12 and 15 should be 3 since the only factors of 15 are 1,3,5,and 15 and 3 is the only factor that 15 shares with 12

7 0

4 years ago

If triangle ABC has the following

Free_Kalibri [48]

Answer:

Measure of side C is 7.14

Step-by-step explanation:

In this question, we are to find the length of the side C.

To get this, we are to employ the use of the cosine formula.

Mathematically, this is calculated as;

c^2 = a^2 +b^2 - 2ab*cos(C)

Where; a = 10 b = 3 and c = 15 degrees

Plugging these values into the equation, we have;

C^2 = 10^3 + 3^2 -2(3)(10)Cos 15

C^2 = 100 + 9 - 57.96

C^2 = 51.04

C = √(51.04)

C = 7.14

7 0

3 years ago

Read 2 more answers

Find the value of x in each of the following<br> 2x/7-3=2

Fynjy0 [20]

Answer:

22x/7=52x=35x= 35/2

Step-by-step explanation:

hope this helps

7 0

3 years ago

Read 2 more answers

Jamie ran a total distance of 6 and 1 over 2 miles during the months of March and April. If Jamie only ran 1 over 6 mile every d

otez555 [7]

Given:

Total distance covered by Jamie = $6\dfrac{1}{2}$ miles

She ran every day = $\dfrac{1}{6}$ miles

To find:

The number of days in which she go for running.

Solution:

Total distance covered by Jamie $=6\dfrac{1}{2}$ miles

$=\dfrac{6\times 2+1}{2}$ miles

$=\dfrac{12+1}{2}$ miles

$=\dfrac{13}{2}$ miles

She ran every day = $\dfrac{1}{6}$ miles

Now,

$\text{Required number of days}=\dfrac{\text{Total distance covered}}{\text{Distance covered each day}}$

$\text{Required number of days}=\dfrac{\dfrac{13}{2}}{\dfrac{1}{6}}$

$\text{Required number of days}=\dfrac{13}{2}\times \dfrac{6}{1}$

$\text{Required number of days}=39$

Therefore, the required number of days is 39.

6 0

3 years ago