Answer:
The 95 percent confidence interval for the true mean metal thickness is between 0.2903 mm and 0.2907 mm
Step-by-step explanation:
We have that to find our 
level, that is the subtraction of 1 by the confidence interval divided by 2. So:
Now, we have to find z in the Ztable as such z has a pvalue of 
.
So it is z with a pvalue of 
, so 
Now, find the margin of error M as such
In which 
is the standard deviation of the population and n is the size of the sample.
The lower end of the interval is the sample mean subtracted by M. So it is 0.2905 - 0.0002 = 0.2903 mm
The upper end of the interval is the sample mean added to M. So it is 0.2905 + 0.0002 = 0.2907 mm
The 95 percent confidence interval for the true mean metal thickness is between 0.2903 mm and 0.2907 mm
Answer:
$125
Step-by-step explanation:
To solve this, we need to find 2.5% of 5,000. To do this, we multiply 5,000 by .025. This gets us 125. That means you earn $125 worth of interest in one year.
Answer:
The missing height is approximately 78.8011 feet.
Step-by-step explanation:
To solve for the height of the kite, you need to use a trigonometry function called sine. Sine - or sin when used to calculate - is most commonly used for right triangles, and the sine of a right triangle angle is equivalent to the side opposite (or the only side of the right triangle that does not help create that angle) of the angle divided by the hypotenuse of the right triangle. So you can now create the following function to solve the height: sin(52°) = 
where x represents the unknown height of the kite. From there, you can get that 
52°
, which equals approximately 78.8011 feet. Since there isn't a specific decimal place to round to, I rounded the answer to four decimals. If your teacher asks you to round to a specific place value, use 78.8011 to get your simplified answer.
Answer:
-7/18
Step-by-step explanation:
cos(2x) = 1 - 2sin²x
cos(2x) = 1 - 2(5/6)²
= 1 - 2(25/36)
= 1 - 25/18
= -7/18
The sum of two irrational numbers, in some cases Will be irrational. However, if the rational parts of the numbers have a 0 sum (cancel each other out), the sum will be rational.
