Answer:
Yes
Step-by-step explanation:
Yes it is possible to solve a quadratic equation that is not factorable over the set of integers.
The solution may vary like Integers, rationals, irrationals or complex solutions.
To find two roots of the equation we can always use the formula given below to solve a quadratic equation,
For the quadratic equation,
, we have,
If the discriminant is greater than , we get complex roots.
Your question: The graph above shows a polynomial function with ___
<h3>Answer: B, a polynomial function with an odd degree and a positive leading coefficient</h3>Step-by-step explanation: If the degree of a polynomial f(x) is even and the leading coefficient is positive, then f(x) → ∞ as x → ±∞. ... If f(x) is an odd degree polynomial with positive leading coefficient, then f(x) →-∞ as x →-∞ and f(x) →∞ as x → ∞.
I hope this helps, mate!
Answer:
y= -8
Step-by-step explanation:
where m is the slope of the line.
m= 0 which is equal to the slope of the line y=9
because both are parallel.