Answer:
15
Step-by-step explanation:
J, K, and L are collinear
J is between K and L
LK = KJ + LJ
LK = 9x + 7
KJ = 2x - 3
LJ = 4x - 8
9x + 7 = (2x - 3) + (4x - 8)
9x + 7 = (2x + 4x) + (-3 - 8)
9x + 7 = 6x + -11
9x + 7 = 6x - 11
9x + 7 - 7 = 6x - 11 - 7
9x = 6x - 18
9x - 6x = 6x - 6x - 18
3x = -18
x = -6
∴ The value of x is -6
Answer:
Step-by-step explanation:
(-4,0) ; (-7, -14)
![d=\sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}\\\\ =\sqrt{(-7-[-4])^{2}+(-14-0)^{2}}\\\\ =\sqrt{(-7+4)^{2}+(-14)^{2}}\\\\=\sqrt{(-3)^{2}+(-14)^{2}}\\\\=\sqrt{9+196} \\\\=\sqrt{205} \\\\=14.3178](https://tex.z-dn.net/?f=d%3D%5Csqrt%7B%28x_%7B2%7D-x_%7B1%7D%29%5E%7B2%7D%2B%28y_%7B2%7D-y_%7B1%7D%29%5E%7B2%7D%7D%5C%5C%5C%5C%20%3D%5Csqrt%7B%28-7-%5B-4%5D%29%5E%7B2%7D%2B%28-14-0%29%5E%7B2%7D%7D%5C%5C%5C%5C%20%3D%5Csqrt%7B%28-7%2B4%29%5E%7B2%7D%2B%28-14%29%5E%7B2%7D%7D%5C%5C%5C%5C%3D%5Csqrt%7B%28-3%29%5E%7B2%7D%2B%28-14%29%5E%7B2%7D%7D%5C%5C%5C%5C%3D%5Csqrt%7B9%2B196%7D%20%5C%5C%5C%5C%3D%5Csqrt%7B205%7D%20%5C%5C%5C%5C%3D14.3178)
Answer: Δx = 0.5
Step-by-step explanation:
We have the interval:
[−3, −1]
and we partition it into 4 equal intervals.
first, the range of our interval is equal to the difference between the extremes, this is:
-1 - (-3) = -1 + 3 = 2
Then, if we divide it into 4, we have 4 segments with a range of:
2/4 = 0.5
Then the subinterval delta is 0.5, and the 4 intervals are:
[−3, -2.5], [−2.5, −2], [−2, −1.5], [−1.5, −1]
The gcf of -18m and 27 is -9 if not then positive 9, but if you want me to also solve the equation its -18m + 27 is -9(2m - 3) i hope it helps!
