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3 years ago

F(x) = (x - 3)(x + 4)

Mathematics

1 answer:

Vladimir [108]3 years ago

5 0

Answer:

f(x)= x^2+x-12

Step-by-step explanation:

FOIL

First= (x)(x)=x^2

Outer=(x)(4)=4x

Inner=(-3)(x)=-3x

Last=(-3)(4)=-12

x^2+4x-3x-12

x^2+x-12

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F(x)= 9x + 2 over 3X^2+5x-12

Maurinko [17]

Here the only limitation on the domain exists when the denominator is equal to zero, as division by zero has no meaning and is not "allowed" because of its meaninglessness. :)

Factor the denominator to find the excluded values of x...

3x^2+5x-12

3x^2+9x-4x-12

3x(x+3)-4(x+3)

(3x-4)(x+3)

So x CANNOT equal 4/3 or -3 (all other real values of x are part of the domain) so the domain is:

x=(-oo, -3),(-3, 4/3),(4/3, +oo)

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3 years ago

Please help i hate geometry

blagie [28]

Answer is b hope this helps brainleist is appreciated

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3 years ago

The patel family went to a festival. the family is made up of 2 adults and 3 children. admission to the festival is $22.00 for a

MArishka [77]

Answer:$89.00

Step-by-step explanation:22 times 2 is 44.

15 times 3 is 45.

44 plus 45 is 89

3 0

2 years ago

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Use algebraic rules of equations to predict the solution type to the system of equations. Include all of your work for full cred

svp [43]

Answer:

The system has infinite solutions

Step-by-step explanation:

For a system of two linear equations it is always true that if one equation is a linear combination of another, then the system will have infinite solutions.

Suppose we have the following system:

$ax + by = c\\dx + hy = f$

If there is a number n for which it is fulfilled that

$= n *$

Then the system has infinite solutions.

In this case the system is:

$x + 2y=10\\3x+6y =30$

Observe that:

$= \frac{1}{3}*$

Then $n =\frac{1}{3}$

The system has infinite solutions

5 0

3 years ago

Using V = lwh, what is an expression for the volume of the following prism? The dimensions of a prism are shown. The height is S

Lubov Fominskaja [6]

<h2>Explanation:</h2><h2></h2>

We know that the volume of a prism is defined by:

$V=lwh \\ \\ \\ Where: \\ \\ l:length \\ \\ w:width \\ \\ h:height \\ \\ \\ l=\frac{d-2}{3d-9} \\ \\ w=\frac{4}{d-4} \\ \\ h=\frac{2d-6}{2d-4}$

Substituting values:

$V=\left(\frac{d-2}{3d-9}\right)\left(\frac{4}{d-4}\right)\left(\frac{2d-6}{2d-4}\right) \\ \\ \\ Simplifying: \\ \\ V=\frac{d-2}{3d-9}\cdot \frac{4}{d-4}\cdot \frac{d-3}{d-2} \\ \\ V=\frac{\left(d-2\right)\cdot \:4\left(d-3\right)}{\left(3d-9\right)\left(d-4\right)\left(d-2\right)} \\ \\ V=\frac{4\left(d-3\right)}{\left(3d-9\right)\left(d-4\right)} \\ \\ V=\frac{4\left(d-3\right)}{3\left(d-3\right)\left(d-4\right)}$

$Finally: \\ \\ \boxed{V=\frac{4}{3\left(d-4\right)}}$

4 0

4 years ago

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