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mixas84 [53]
3 years ago
13

Ahh please help meeee

Mathematics
2 answers:
Anna [14]3 years ago
8 0
C is also the best answer
Andrews [41]3 years ago
3 0
The answer would be c
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A study found that a 95% confidence interval for the mean μ of a particular population was computed from a random sample of 1200
kotykmax [81]

Answer:

95% confidence interval for the mean μ is (6,14)

The Population mean μ lies between ( 6, 14 )

Step-by-step explanation:

<u><em>Explanation</em></u>:-

Given random sample 'n' = 1200

95% confidence interval for the mean μ is determined by

        (x^{-} -Z_{\alpha } \frac{S.D}{\sqrt{n} } , x^{-} +Z_{\alpha } \frac{S.D}{\sqrt{n} } )

Level of significance = 95% 0r 0.05

Z₀.₀₅ = 1.96

   (x^{-} -Z_{\alpha } \frac{S.D}{\sqrt{n} } , x^{-} +Z_{\alpha } \frac{S.D}{\sqrt{n} } ) = 10 ± 4

Mean of the small sample = 10

95% of confidence intervals are

                         ( 10 ±4 )

                  ( 10 -4 , 10+4)

                  ( 6 , 14 )

95% confidence interval for the mean μ lies between ( 6, 14 )

8 0
3 years ago
Solve for the variable b. 5a(b - c ) = d
Liula [17]
5a(b-c)=d. Here, we are trying to isolate the variable b.
Divide both sides by 5a: b-c=d/(5a)
Add c to both sides: b= \frac{d}{5a} +c
3 0
3 years ago
Read 2 more answers
What are the following expressions that are equivalent to 0.25.
wlad13 [49]

Answer:

Step-by-step explanation:

0.25=25/100=1/4

4 0
3 years ago
A young sumo wrestler goes on a special diet to gain weight.
Ilia_Sergeevich [38]

Answer:

10.8 kg

Step-by-step explanation:

w = 80 + 5.4t

At time 0, when he starts the diet, his initial weight is

w = 80 + 5.4(0)

w = 80

80 kg.

After 2 months, t = 2. His weight is

w = 80 + 5.4t

w = 80 + 5.4(2)

w = 80 + 10.8

w = 90.8

90.8 kg.

His gain in 2 months was 90.8 kg - 80 kg = 10.8 kg

Answer: 10.8 kg

8 0
3 years ago
Read 2 more answers
Polygon ABCD is dilated, rotated, and translated to form polygon A′B′C′D′. The endpoints of AB are at (0, -7) and (8, 8), and th
Anton [14]

Rotation and translation are rigid transformations, they don't change figure sizes. Dilation change figure sizes increasing or decreasing them by scale factor.

First, find AB and A'B' by the formula:

AB=\sqrt{(x_B-x_A)^2+(y_B-y_A)^2}= \sqrt{(8-0)^2+(8-(-7))^2}=\sqrt{8^2+15^2}=\sqrt{64+225}=\sqrt{289}=17,\\ \\A'B'=\sqrt{(x_{B'}-x_{A'})^2+(y_{B'}-y_{A'})^2}= \sqrt{(2-6)^2+(1.5-(-6))^2}=\sqrt{4^2+7.5^2}=\sqrt{16+56.25}=\sqrt{72.25}=8.5.

As you can see AB=2A'B'. This means that the segment AB was decreased twice to form segment A'B'. Then the scale factor is 1/2.

8 0
3 years ago
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