Answer:
P(X= k) = (1-p)^k-1.p
Step-by-step explanation:
Given that the number of trials is
N < = k, the geometric distribution gives the probability that there are k-1 trials that result in failure(F) before the success(S) at the kth trials.
Given p = success,
1 - p = failure
Hence the distribution is described as: Pr ( FFFF.....FS)
Pr(X= k) = (1-p)(1-p)(1-p)....(1-p)p
Pr((X=k) = (1 - p)^ (k-1) .p
Since N<=k
Pr (X =k) = p(1-p)^k-1, k= 1,2,...k
0, elsewhere
If the probability is defined for Y, the number of failure before a success
Pr (Y= k) = p(1-p)^y......k= 0,1,2,3
0, elsewhere.
Given p= 0.2, k= 3,
P(X= 3) =( 0.2) × (1 - 0.2)²
P(X=3) = 0.128
Answer:
lies you wont give brainliest
Step-by-step explanation:
Answer:
Three acute angles.
Explanation:
There are always three acute angles in an acute triangle.
The hyperbolic cos (cosh) is given by
cosh (x) = (e^x + e^-x) / 2
The slope of a tangent line to a function at a point is given by the derivative of that function at that point.
d/dx [cosh(x)] = d/dx[(e^x + e^-x) / 2] = (e^x - e^-x) / 2 = sinh(x)
Given that the slope is 2, thus
sinh(x) = 2
x = sinh^-1 (2) = 1.444
Therefore, the curve of y = cosh(x) has a slope of 2 at point x = 1.44
(72/80)x90=81
Divide seventy-two by eight and multiply it Ninety.
