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3 years ago

Need help!!!!!!How do I do this?

Mathematics

1 answer:

tiny-mole [99]3 years ago

6 0

Rotate 90 degrees clockwise which means to rotate it to the right. so the thing would be in the top right corner.
hope this helped.

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What is the solution of 3 sqrt x+8=-4?

ryzh [129]

Answer:

$x=-72$

Step-by-step explanation:

The given equation is $\sqrt[3]{x+8}=-4$ .

We cube both sides of this equation to obtain;

$(\sqrt[3]{x+8})^3=(-4)^3$ .

This implies that;

$(x+8)=-64$

We group similar terms to obtain;

$x=-64-8$

We simplify the right hand side of the equation to obtain;

$x=-72$

Therefore x=-72 is the solution of the given equation.

4 0

3 years ago

What is the value of the expression below when z=7 6z-2

horsena [70]

Answer:

the answer is 40

Step-by-step explanation:

U multiply then subtract.

6 0

3 years ago

Use this information to answer the following 7 questions.

Phantasy [73]

Answer:

1) b. an experimental study

2) a. μ1=μ2=μ3

3) a. MSE

4) MSTR =85.735

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6) b. 0.004

7) a. We reject the null hypothesis

8) b. Yes

Step-by-step explanation:

See the attached image

8 0

3 years ago

In a ∆ABC , angle A + Angle B = 125° and Angle B + Angle C = 150° . Find all the angles of ∆ABC.

mel-nik [20]

$\large\underline{\sf{Solution-}}$

Given that,

In triangle ABC

$\purple{\rm :\longmapsto\:\angle A + \angle B = 125 \degree \: - - - (1) }$

$\purple{\rm :\longmapsto\:\angle B + \angle C = 150 \degree \: - - - (2)}$

We know,

Sum of all interior angles of a triangle is supplementary.

$\purple{\rm :\longmapsto\:\angle A + \angle B + \angle C = 180\degree }$

On adding equation (1) and (2), we get 

$\purple{\rm :\longmapsto\:\angle A + \angle B + \angle B + \angle C = 125\degree + 150 \degree \:}$

$\purple{\rm :\longmapsto\:\angle A + \angle B + \angle C + \angle B = 275\degree \:}$

$\purple{\rm :\longmapsto\:180\degree + \angle B = 275\degree \:}$

$\purple{\rm :\longmapsto\:\angle B = 275\degree - 180\degree \:}$

$\purple{\rm :\longmapsto\:\angle B = 95\degree \:}$

On substituting the value in equation (1) and (2), we get

$\purple{\rm :\longmapsto\:\angle A + 95\degree = 125\degree }$

$\purple{\rm :\longmapsto\:\angle A = 125\degree - 95\degree }$

$\purple{\rm :\longmapsto\:\angle A = 30\degree }$

Also, from equation (2), we get

$\purple{\rm :\longmapsto\:95\degree + \angle C = 150\degree }$

$\purple{\rm :\longmapsto\:\angle C = 150\degree - 95\degree }$

$\purple{\rm :\longmapsto\:\angle C = 55\degree }$

Hence,

$\begin{gathered}\begin{gathered}\bf\: \rm\implies \:\begin{cases} &\sf{\angle A = 30\degree } \\ \\ &\sf{\angle B = 95\degree } \\ \\ &\sf{\angle C = 55\degree } \end{cases}\end{gathered}\end{gathered}$

3 0

3 years ago

Read 2 more answers

Solve the system. {y=5/6x+1 {−x+y=2

astraxan [27]

You can substitute the value of y(5/6 x + 1) from the first equation for y in the second and get $-x + ( \frac{5}{6} x+1) = 2
$ which becomes $- \frac{1}{6} x + 1 -1=2-1
$ and you get

3 0

4 years ago

Read 2 more answers