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Andreyy89
3 years ago
7

Need help!!!!!!How do I do this?

Mathematics
1 answer:
tiny-mole [99]3 years ago
6 0
Rotate 90 degrees clockwise which means to rotate it to the right. so the thing would be in the top right corner.
hope this helped.

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Harish
Artist 52 [7]

Answer:

Step-by-step explanation:

Distance traveled in 1\frac{4}{5} hours = \frac{3}{10}

Distance traveled in 1 hour = \frac{3}{10} ÷ 1\frac{4}{5}

          =\frac{3}{10} ÷ \frac{9}{5}

          = \frac{3}{10}*\frac{5}{9}\\\\=\frac{1}{2}*\frac{1}{3}\\\\=\frac{1}{6}

distance traveled in 3 1/5 hours = \frac{1}{6}*3\frac{1}{5}

 ==\frac{1}{6}*\frac{8}{5}\\\\=\frac{1}{3}*\frac{4}{5}\\\\=\frac{4}{15}

5 0
2 years ago
Jacon walks 70.4 feet in 0.2 hours. If he walks at the same rate the whole time, what is his spped in feet per hour?
timofeeve [1]

Answer:

12.7

Step-by-step explanation:

6 0
2 years ago
Read 2 more answers
In order to determine whether or not a variable type of process is in control (whereoutput can be measured, not just classified
Tema [17]

Answer:

i dont know

Step-by-step explanation:

just working

6 0
3 years ago
In a group of 10 ​kittens, 5 are female. Two kittens are chosen at random. ​a) Create a probability model for the number of male
olya-2409 [2.1K]

Answer:

(b) Expected number of male kitten E(x) = 1

(c) Standard deviation is ±\frac{2}{3}.

Step-by-step explanation:

Given that,

Number of kittens in a group are 10. Out of these 5 are female.

To find:- (a) create a probability model of male kitten chosen.

    So,  total number of kitten = 10

           number of female kitten = 5    

then, Number of male kitten = 10-5= 5

Now total number of ways to choosing two kittens from group of 10 = ^{10} C_{2}

                                                                                                                 = \frac{10!}{2!\times8!}

                                                                                                                 = 45

for choosing (i) No male P(x=0) = P(Two female) =  \frac{^{5} C_{2}}{45}

                                                                           = \frac{2}{9}

                     (ii) 1 male P(x=1) = P(1 male and 1 female) = \frac{^{5} C_{1}\times^{5} C_{1}}{45} =  \frac{25}{45} =\frac{5}{9}

                     (iii) 2 male P(x=2)= P(2 male) =\frac{^{5} C_{2}}{45} =  \frac{2}{9}

      x_{i}                             0                     1                      2

P(X=x_{i})                           \frac{2}{9}                      \frac{5}{9}                      \frac{2}{9}

(b) what is expected number of male kittens chosen ?

    Expected number of male kitten E(x) =  o\times \frac{2}{9} + 1\times \frac{5}{9} + 2\times\frac{2}{9}

                                                                  = 1

(c) what is standard deviation ?

                              \sigma(x) = \sqrt{ (E(x^{2} )-(Ex)^{2})

No,                          

                               Ex^{2} =o\times \frac{2}{9} + 1\times \frac{5}{9} + 4\times\frac{2}{9}

                                       = \frac{13}{9}

                               \sigma(x)=\sqrt{\frac{13}{9} - 1 }=\sqrt{\frac{4}{9} }  

                                       = ± \frac{2}{3}

                               

6 0
3 years ago
Is 2.5/3=75% equivalent
xenn [34]
Yes because I just took the test
5 0
3 years ago
Read 2 more answers
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