Answer:
f(2x + 4) = -4x² - 16x - 15
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Distributive Property
<u>Algebra I</u>
- Terms/Coefficients
- Expanding (FOIL)
Step-by-step explanation:
<u>Step 1: Define</u>
<em>Identify</em>
f(x) = 1 - x²
<u>Step 2: Evaluate</u>
- Substitute in <em>x</em> [Function f(x)]: f(2x + 4) = 1 - (2x + 4)²
- Expand [FOIL]: f(2x + 4) = 1 - (4x² + 16x + 16)
- (Parenthesis) Distribute negative: f(2x + 4) = 1 - 4x² - 16x - 16
- Combine like terms: f(2x + 4) = -4x² -16x - 15
The answer seems to be D!!
Answer: He will practice both on every 15 days.
Step-by-step explanation:
Given: Jaquan practices soccer every 3 days.
He practices basketball every 5 days Jaquan practiced both today.
The number of days until he practices both = Least common multiple of 3 and 5
= 3 x 5 [Both are primes]
= 15
Hence, he will practice both on every 15 days.
- Least common multiple of two numbers p and q is the smallest number that is divisible by both p and q.
1.02 is the correct answer i hope this helped<3
For the answer to the question above,
1 + nx + [n(n-1)/(2-factorial)](x)^2 + [n(n-1)(n-2)/3-factorial] (x)^3
<span>1 + nx + [n(n-1)/(2 x 1)](x)^2 + [n(n-1)(n-2)/3 x 2 x 1] (x)^3 </span>
<span>1 + nx + [n(n-1)/2](x)^2 + [n(n-1)(n-2)/6] (x)^3 </span>
<span>1 + 9x + 36x^2 + 84x^3 </span>
<span>In my experience, up to the x^3 is often adequate to approximate a route. </span>
<span>(1+x) = 0.98 </span>
<span>x = 0.98 - 1 = -0.02 </span>
<span>Substituting: </span>
<span>1 + 9(-0.02) + 36(-0.02)^2 + 84(-0.02)^3 </span>
<span>approximation = 0.834 </span>
<span>Checking the real value in your calculator: </span>
<span>(0.98)^9 = 0.834 </span>
<span>So you have approximated correctly. </span>
<span>If you want to know how accurate your approximation is, write out the result of each in full: </span>
<span>1 + 9(-0.02) + 36(-0.02)^2 + 84(-0.02)^3 = 0.833728 </span>
<span> (0.98)^9 = 0.8337477621 </span>
<span>So it is correct to 4</span>
