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nikitadnepr [17]
3 years ago
9

What is the cost of 2 kilograms of flour is 3 kg cost $4.86 in the unit price for each package of flour is the same

Mathematics
1 answer:
11111nata11111 [884]3 years ago
5 0

Answer:3.24

Step-by-step explanation:

Divide 4.86 by 3 then you will get 1.62 . You mutiply 1.62 times 2 to get 3.24

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(x-h)^2+(y-k)^2=r^2
dimaraw [331]

Answer:

(x-2)^2 + (y - 5)^2 = 16

Step-by-step explanation:

Given the standard form of an equation of a circle

(x-h)^2+(y-k)^2=r^2

If (h, k) = (5,2) and r = 4

Substitute

(x-2)^2 + (y - 5)^2 = 4^2

(x-2)^2 + (y - 5)^2 = 16

Hence the required equation is (x-2)^2 + (y - 5)^2 = 16

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Which of these is a correct statement regarding payday loans?
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They're easier to get than both mortgages and car loans
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We roll two fair 6-sided dice. Each of the 36 possible outcomes is assumed to be equally likely. (a) Given that the roll results
boyakko [2]

Answer:

a) \frac{1}{7}

b) \frac{2}{15}

Step-by-step explanation:

Given : We roll two fair 6-sided dice. Each of the 36 possible outcomes is assumed to be equally likely.

The outcomes are :

(1, 1) (1, 2)  (1, 3)  (1, 4)  (1, 5)  (1, 6)

(2, 1) (2, 2) (2, 3) (2, 4) (2, 5) (2, 6)

(3, 1) (3, 2) (3, 3) (3, 4) (3, 5) (3, 6)

(4, 1) (4, 2) (4, 3) (4, 4) (4, 5) (4, 6)

(5, 1) (5, 2) (5, 3) (5, 4) (5, 5) (5, 6)

(6, 1) (6, 2) (6, 3) (6, 4) (6, 5) (6, 6)

(a) Given that the roll results in a sum of 3 or more, find the conditional probability that doubles (the first and the second rolls result in the same number) are rolled.

Let P(A) be the probability of event that the roll results in a sum of 3 or more.

Except (1,1) rest sum is 3 or greater than 3.

So, P(A)=\frac{35}{36}

Now, P(A and B) is that the roll results in a sum of 3 or more and that doubles (the first and the second rolls result in the same number) are rolled.

i.e. (2,2), (3,3), (4,4), (5,5), (6,6) - 5

P(A\cap B)=\frac{5}{36}

The conditional probability is given by,

P(B|A)=\frac{P(A\cap B)}{P(A)}

P(B|A)=\frac{\frac{5}{36}}{\frac{35}{36}}

P(B|A)=\frac{5}{35}

P(B|A)=\frac{1}{7}

(b) Given that the two dice land on different numbers, find the conditional probability that the sum is 5.

Let P(A) be the probability of event that two dice land on different numbers.

Except (1,1),(2,2), (3,3), (4,4), (5,5), (6,6) rest two dice land on different numbers.

So, P(A)=\frac{30}{36}

Now, P(A and B) is that two dice land on different numbers and the sum is 5.

i.e. (1,4), (2,3), (3,2), (4,1) - 4

P(A\cap B)=\frac{4}{36}

The conditional probability is given by,

P(B|A)=\frac{P(A\cap B)}{P(A)}

P(B|A)=\frac{\frac{4}{36}}{\frac{30}{36}}

P(B|A)=\frac{4}{30}

P(B|A)=\frac{2}{15}

4 0
3 years ago
$299 tv with 15% discount
Nuetrik [128]
The answer is 254. You want 299 with 15% off
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Your brother ordered some pens on the internet. It cost 2$ for each pen and the shipping fee is 3$. If your brother paid a total
Mars2501 [29]

Answer:

10pens

Step-by-step explanation:

23-3=20

20÷2=10

5 0
3 years ago
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