All categories

3 years ago

How do you wright twelve and a half trillion in scientific notation?

Mathematics

2 answers:

AveGali [126]3 years ago

7 0

The correct answer is:

$1.25\times 10^{13}$

Explanation:

First we must determine where the trillions place is in place value. The first group of 3 digits is thousands; the second group of 3 is the millions; the third group of 3 is the billions; and the 4th group of 3 is the trillions. This means that 1 trillion would be a 1 with 12 zeros following it.

This means that 12 trillion would be 12 with 12 zeros following it. The "half" would be a 5 immediately after the 12, which would give us

12,500,000,000,000

Scientific notation requires 1 non-zero digit in front of the decimal. This means we would have 1.25. The exponent of 10 is the number of decimal places we must move the decimal; for this number, that is 13 places. This gives us

$1.25\times 10^{13}$

leva [86]3 years ago

3 0

twelve and a half trillion = 12.5 x 10^12
1.25 x 10^13 in scientific notation

You might be interested in

Can someone help me please

alexandr402 [8]

Answer:

y = x + 2

Step-by-step explanation:

You can find the slant asymptote using polynomial long division because the numerator is one degree higher than the denominator.

(x^2+x+4)/(x-1)

I'm not sure how to show long division but you should get:

x+2 with remainder 6

Then your slant asymptote is y = x + 2

You can graph it on Desmos to verify

8 0

2 years ago

How would i solve this does anyone know?

KATRIN_1 [288]

You need to use pythagorean’s theorem. so a^2+b^2=c^2.

in this case it would be 6^2+8^2=c2

36+64=100

the square root of 100 is 10

x=10

7 0

2 years ago

Which statement is not a step used when constructing an inscribed square?

V125BC [204]

Where is the multiple choice answers ?

6 0

3 years ago

Someone help, it’s 3:00 am and I gotta get this done and I’m so tired just someone help me, please.

romanna [79]

Answer:

1) 31.1

2) 2.5

3) 1.6

4) 0.9

5) 5120

6) 1.7

7) 972

8) 0.02

Step-by-step explanation:

6 0

4 years ago

The position of an object moving vertically along a line is given by the function s(t)= −16t^2 +128t. Find the average velocity

olchik [2.2K]

Answer:

a) 48

b) 64

c) 80

d) -16h + 96

Step-by-step explanation:

To find the average velocity of an object over an interval you need to find the distance it moved during the interval and divide by the time.

a) To find the distance it moved, we need to know the position the object was at the start of the interval and the position it was at the end of the interval. I will suppose the position is in meters and time is in seconds.

The position at the start of the interval is s(1) = -16*1² + 128(1) = 112m

The position at the end of the interval is s(4) = -16*4² + 128(4) = 256m

So, from the start to the end of the interval, the object moved 256-112 = 144m in 4-1 = 3 seconds.

Av = 144/3 = 48 m/s

b) From a), we already know s(1) = 112.

We need to find s(3)

s(3) = -16*3² + 128*3 = -144 + 384 = 240m.

From the start to the end of the interval, the object moved 240-112 = 128m in 3-1 = 2 seconds.

Av = 128/2 = 64 m/s

c) From a), s(1) = 112

We need to find s(2)

s(2) = -16*2² + 128*2 = -64 + 256 = 192m

From the start to the end of the interval, the object moved 192-112 = 80m in 2-1 = 1 second.

Av = 80/1 = 80m/s

d) From a), s(1) = 112

We need to find s(1+h).

s(1+h) = -16*(1+h)² + 128(1+h) = -16(1 + 2h + h²) + 128 + 128h = -16 - 32h - 16h² + 128 + 128h = -16h² + 96h + 112.

From the start to the end of the interval, the object moved -16h² + 96h + 112 - 112 = (-16h² + 96h)m in 1+h-1 = h seconds.

Av = (-16h² + 96h)/h = h(-16h+96)/h = -16h + 96

7 0

4 years ago