Answer: In this compound, phosphorous and oxygen act together as one charged particle, which is connected to magnesium, the other charged particle.
Explanation:
Formula
V/T = V1/T1
Givens
V = 430 L
T = - 42 °C = - 42 + 273 = 231°K
V1 = ??
T1 = 18°C + 273 = 291°K
The pressure is a constant.
Solution
420/231 = V1/291 Multiply by 291
420*291 / 231 = V1
V1 = 122220 / 231
V1 = 521.1 L
<span>7.379 * 10^(-4) is measured, hence prone to error, either human error or via measuring device. In this case,
100 cm = 1 m is written in stone and is unquestionable.
The density of the gold is 19.3 g/cm^3 and could be an approximation.
The approximation is good to at least one night.</span>
The density of the patient's hemoglobin in their blood in units of g/ml = 0.2g/mL
<h3>Calculation of hemoglobin density</h3>
Hemoglobin is the red blood cell pigment that transports oxygen to the body cells.
1 gram of hemoglobin = 2.15mg
Blood volume of the patient is = 4.9ml
Density= mass/volume
Therefore the density of patients hemoglobin= 1/4.9 = 0.2g/mL
Learn more about hemoglobin here:
brainly.com/question/8197071
Answer:
455.4 g
Explanation:
Data given:
no. of moles of (NH₄)₂SO₄= 3.45 mol
mass of (NH₄)₂SO₄ = ?
Solution
Formula will be used
no.of moles = mass in grams / molar mass
Rearrange the above equation for mass
mass in grams = no. of moles x molar mass . . . . . . . . (1)
molar mass of (NH₄)₂SO₄
molar mass of (NH₄)₂SO₄ = 2(14 + 4(1)) + 32 + 4(16)
molar mass of (NH₄)₂SO₄ = 2 (14 +4) + 32 + 64
molar mass of (NH₄)₂SO₄ = 2 (18) + 32 + 64
molar mass of (NH₄)₂SO₄ = 36 + 32 + 64 = 132 g/mol
Put values in equation 1
mass in grams = 3.45 mole x 132 g/mol
mass in grams = 455.4 g
So,
mass of (NH₄)₂SO₄ = 455.4 g
