well the atomic number is 7 the number of protons is also equal to 7 .
hope this helps
1) Chemical reaction (thermal decomposition)
2NaHCO3 (s) ---> Na2CO3 (s) + H2O (g) + CO2(g)
2) Reasoning
The lost of mass is due to the lost of the gases H2O and CO2.
So, you can calculate the mass of Na2CO3 obtained from 1.000 g NaHCO3, and the difference will be the mass lost.
2) Convert 1.000 g of NaHCO3 to number of moles
molar mass NaHCO3: 1*23g/mol + 1*1g/mol + 1*12g/mol + 3*16g/mol = 84 g/mol
number of moles = mass in grams / molar mass = 1.000 g / 84 g/mol = 0.01190 moles
3) Use therotecial molar ratios:
2 moles NaHCO3 : 1 mol Na2CO3
=> 0.01190 mol NaHCO3 / x = 2 mol NaHCO3 / 1mol Na2CO3
=> x = 1mol Na2CO3 * 0.01190 mol NaHCO3 / 2 mol NaHCO3
=> x = 0.00595 mol Na2CO3
4) Convert 0.0595 mol Na2CO3 to mass
molar mass Na2CO3: 2*23g/mol + 1*12g/mol + 3*16g/mol = 106 g/mol
mass in grams = number of moles * molar mass = 0.00595 mol * 106 g/mol = 0.6307 g
5) lost mass
1.000g - 0.6307g = 0.3693 g
Answer: 0.3693 g
Answer:
and
Explanation:
All the carbon group atoms, having four valence electrons, form covalent bonds with nonmetal atoms; carbon and silicon cannot lose or gain electrons to form free ions, whereas germanium, tin, and lead do form metallic ions but only with two positive charges
the similarities is that Both carbon and silicon commonly form compounds, easily sharing electrons with other elements. Carbon will make multiple bonds with other carbon molecules by forming single, double and triple covalent bonds. ... Carbon and silicon are often combined, with carbon serving as silicon's backbone.
Answer:
ClO⁻(aq) + I⁻(aq) → Cl⁻(aq) + IO⁻(aq)
Explanation:
The reactions are:
(1) ClO⁻(aq) + H₂O(l) → HClO(aq) + OH⁻(aq) [fast]
(2) I⁻(aq) + HClO(aq) → HIO(aq) + Cl⁻(aq) [slow]
(3) OH⁻(aq) + HIO(aq) → H₂O(l) + IO⁻(aq) [fast]
By adding up the 3 equations we get:
ClO⁻(aq) + <em>H₂O(l)</em> + I⁻(aq) + <em>HClO(aq)</em> + <em>OH⁻(aq)</em> + <em>HIO(aq)</em> → <em>HClO(aq)</em> + <em>OH⁻(aq)</em> + <em>HIO(aq)</em> + Cl⁻(aq) + <em>H₂O(l)</em> + IO⁻(aq)
And by canceling common terms on both sides, we can get the overall equation:
ClO⁻(aq) + I⁻(aq) → Cl⁻(aq) + IO⁻(aq)
Therefore, the overall equation is ClO⁻(aq) + I⁻(aq) → Cl⁻(aq) + IO⁻(aq).
I hope it helps you!
