The answwer to the type of hardware is led lighting it does not need a inverter
Answer:
(11n-5) / 12 is correct answer.
Explanation:
The Probability that key will match to nth term = 1/2
The Probability that key will match to n-1th term = 1/3
As all other probabilities are equal
The Total Probability that key matches to any of 1 to n-2 index = 1 - 1/2 - 1/3 = 1/6
The Probability that key matches to any of 1 to n-2 index = (1/6) / n-2 = (1/6)* (n-2))
Let P(i) = Probability that key matches to ith index.
The Average time complexity = 22 i=1 P(i) * i
The Average time complexity = 1/(6(n-2) * ( sum of 1 to n-2 ) + (n-1) / 3 + n/2
The Average time complexity = 1/(6(n-2) * ( n-2)*(n-1) / 2 + ( n-1) / 3 + n/2
The Average time complexity = 1/6 * (n-1)/2 + (n-1)/3 + n/2
The Average time complexity = (n-1)/12 + (n-1)/3 + n/2
The Average time complexity = (n-1 + 4 * n - 4 * 1 +6 * n)/12
The Average time complexity = 11n-5 / 12
so (11n-5) / 12 is correct answer.
Answer:
import java.util.Scanner;
public class ArraysKeyValue {
public static void main (String [] args) {
final int SIZE_LIST = 4;
int[] keysList = new int[SIZE_LIST];
int[] itemsList = new int[SIZE_LIST];
int i;
keysList[0] = 13;
keysList[1] = 47;
keysList[2] = 71;
keysList[3] = 59;
itemsList[0] = 12;
itemsList[1] = 36;
itemsList[2] = 72;
itemsList[3] = 54;
/* Your solution goes here */
for ( i = 0; i < SIZE_LIST; i++){
if (keysList[i]>50){
System.out.println(itemsList[i] + " "); } }
System.out.println("");
}
}
Explanation:
I will explain the whole program flow.
- There are two arrays here
- The first list (keysList) contains the following elements:
13 element at first position of the array (0th index)
47 element at second position of the array (1st index)
71 element at third position of the array (2nd index)
59 element at fourth position of the array (3rd index)
- The other list (itemsList) contains the following elements:
12 element at first position of the array (0th index)
36 element at second position of the array (1st index)
72 element at third position of the array (2nd index)
54 element at fourth position of the array (3rd index)
- The size of the array elements is fixed which is 4 and is stored in the variable SIZE_LIST.
- Then the loop starts. The loop contains a variable i which is initialized to 0. First it checks if the value of i is less than the size of the list. It is true as SIZE_LIST=4 and i=0.
- So the program control enters the body of the loop.
- In first iteration, IF condition checks if the i-th element of the keysList is greater than 50. As i=0 So the element at 0th index of the keysList is 13 which is not greater than 50 so the body of IF statement will not execute as the condition evaluates to false. The value of i increments by 1 so now i becomes 1.
- In next iteration loop again checks if the value of i is less than the size of the list which is true again so the body of the loop executes.
- IF condition checks if the i-th element of the keysList is greater than 50. As i=1 So the element at 1st index of the keysList is 47 which is not greater than 50 so the body of IF statement will not execute as the condition evaluates to false. The value of i is incremented by 1 so now i becomes 2.
- In next iteration loop again checks if the value of i is less than the size of the list which is true again as i= 2 which is less than SIZE_LIST so the body of the loop executes.
- IF condition checks if the i-th element of the keysList is greater than 50. As i=2 So the element at 2nd index of the keysList is 71 which is greater than 50 so the body of IF statement is executed as the condition evaluates to true. So in the body of the IF statement there is a print statement which prints the i-th element of the itemsList. As i = 2 so the value at the index 2 of the itemsList is displayed in the output which is 72. Next value of i is incremented by 1 so now i becomes 3.
- In next iteration loop again checks if the value of i is less than the size of the list which is true again as i= 3 which is less than SIZE_LIST so the body of the loop executes.
- IF condition checks if the i-th element of the keysList is greater than 50. As i=3 So the element at 3rd index of the keysList is 59 which is greater than 50 so the body of IF statement is executed as the condition evaluates to true. So in the body of the IF statement there is a print statement which prints the i-th element of the itemsList. As i = 3 so the value at the index 3 of the itemsList is displayed in the output which is 54. Next value of i is incremented by 1 so now i becomes 4.
- In next iteration loop again checks if the value of i is less than the size of the list which is now false as i=4 which is equal to the SIZE_LIST= 4. So the loop breaks.
- So the output of the above program is:
72
54
Answer:
int k;
double d;
char s[10];
cin >> k >> d >> s;
cout << s << " " << d << " " << k << "\n" << k << " " << d << " " << s;
Explanation
First Step (declare K, d, s) so they can store a integer
int k;
double d;
char s[10];
Second Step (read in an integer, a real number and a small word)
cin >> k >> d >> s;
Third Step ( print them out )
cout << s << " " << d << " " << k << "\n" << k << " " << d << " " << s;
Answer:
The errors in the loop condition such that it is not giving desired results or it is not running accordingly.There are different types of loop errors which are as following:-
1.Infinite loop:-When the is not able to stop then the error is called infinite loop. for ex:-
int i=1;
while(i!=0)
{
cout<<"I am King"<<endl;
i++;
}
2.Off by one error:-This error mostly happens in loop for arrays as indexing of the array is from 0 to size-1 .So looping over the array up to the size is a off by one error.
3.Equality v/s assignment operator error:-In this error the condition in the loop is like this d=f which is wrong since = is assignment operator it assigns the value of f to d while d==f checks that the value of d and f are equal or not.
4.&& v/s || loop error:- In this error we use and operator (&&) instead of or operator (||) and vice versa.
symptoms of loop errors are not the desired output.
