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3 years ago

8

If $10,000 is invested at a rate of 2.5 percent for 5 years, how much money is in the account at the end of the term?

2 answers:

IgorLugansk [536]3 years ago

8 0

Your answer would be $400,000 or 400 thousand dollars.

The reason is, $10,000 is at a rate of 2.5 percent for 5 years, and so the percentage needs to multiply by 40 to get to 100%, (The full investment) so 40 needs to multiply by $10,000 for your answer. Thank you and hope this helps.

Vladimir [108]3 years ago

4 0

10,000(1 + .025 x 5)
11,250

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In two or three sentences explain how you would solve for the real solutions of the following equation: please help asap!!

g100num [7]

the real solutions for the equation $x^{3}=-64$ are -

$x=4,2+-2\sqrt{3i}$

Step-by-step explanation:

$x^{3}$ = $- 64$

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We can write 64 as $4^{3}$

$x^{3}$ + $4^{3}$ = 0

using the identity ( $x^{3}+y^{3} = (x+y)(x^{2} -xy+y^{2} )$ )

we get,

= $(x+4) (x^{2} -x*4+4^{2} )$

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solving the quadratic equation ,

$x^{2} -4x+16$ =0

solutions of this quadratic equation can be obtained by

$x=-b +- \sqrt{b^{2}-4ac } /2a$

let use y for factors

$x=-(-4x)+-\sqrt{(-4x^{2} )-4*x^{2} *16} / 2*x^{2}$

$x=4x+-\sqrt{16x^{2} -64x^{2} } /2x^{2}$

$x=4+-\sqrt{16-64}/2$

$x=4+-4\sqrt{3i} /2$

<u /> $x=2+-2\sqrt{3i}$ ..................(2)

from the equation 1 we have,

$x-4=0$

which gives solution $x=4$

and from equation 2 we got $x=2+-2\sqrt{3i}$

so the real solutions for the equation $x^{3}=-64$ are -

$x=4,2+-2\sqrt{3i}$

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3 years ago

Diamond deposited $300 in a savings account that has a 2% interest rate per

Alexxandr [17]

Answer:

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Step-by-step explanation:

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Harman [31]

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total outcome

therefore p(1)=

$\frac{2}{12}$

N. B, a dice has 6faces so 2dice has 12 faces

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3 years ago

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aliya0001 [1]

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Hitman42 [59]

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