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3 years ago

Organize the following expressions from greatest to least by number of terms:

1 answer:

4 0

1- D. 9x2yz
2- C. 2x2y + x2 − 3x + 4
3- A. x + 2xyz
4- B. 3x + y + z

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What is x2 – 6 = 16x + 30 rewritten in standard form, then factored?

kaheart [24]

Answer:

Step-by-step explanation:

$x^2-6=16x+30\\\mathrm{Subtract\:}30\mathrm{\:from\:both\:sides}\\x^2-6-30=16x+30-30\\Simplify\\x^2-36=16x\\\mathrm{Subtract\:}16x\mathrm{\:from\:both\:sides}\\x^2-36-16x=16x-16x\\\Simplify\\x^2-16x-36=0$

5 0

3 years ago

Dean Halverson recently read that full-time college students study 20 hours each week. She decides to do a study at her universi

romanna [79]

Answer: The p-value is 0.154.

Step-by-step explanation:

Since we have given that

We claim that

Null hypothesis :

$H_0:\mu=20$

Alternate hypothesis :

$H_1:\mu$

Population mean = 20 hours

Sample mean = 18.5 hours

Sample standard deviation = 4.3 hours

Sample size n = 35

So, test statistic would be

$z=\dfrac{\bar{X}-\mu}{\dfrac{\sigma}{\sqrt{n}}}\\\\z=\dfrac{18.5-20}{\dfrac{4.3}{\sqrt{35}}}\\\\z=\dfrac{-1.5}{0.726}\\\\z=-2.066$

So, the p value would be 0.154.

Hence, the p-value is 0.154.

4 0

3 years ago

Simplify Rewrite the expression in the form x ^ n X^ 2 * x ^ - 12 =

Natalija [7]

Step-by-step explanation:

Given

$= {x}^{2} \times {x}^{ - 12 } \\ = {x}^{2 - 12} \\ = {x}^{ - 10}$

Hope it will help :)

8 0

3 years ago

Read 2 more answers

Let V=ℝ2 and let H be the subset of V of all points on the line 4x+3y=12. Is H a subspace of the vector space V?

sergejj [24]

Answer:

No, it isn't.

Step-by-step explanation:

We have $V=IR^{2}$ and let $H$ be the subset of $V$ of all points on the line

$4x+3y=12$

We need to find if $H$ is a subspace of the vector space $V$ .

In $IR^{2}$ all the possibilities for own subspace of the vector space $IR^{2}$ are :

$IR^{2}$ itself.

The vector $0_{IR^{2}}=\left[\begin{array}{c}0&0\end{array}\right]$

All lines in $IR^{2}$ that passes through the origin ( $0_{IR^{2}}=\left[\begin{array}{c}0&0\end{array}\right]$ )

We know that $H$ is the subset of $IR^{2}$ of all points on the line $4x+3y=12$

If we look at the equation, the point $\left[\begin{array}{c}0&0\end{array}\right]$ doesn't verify it because :

$4x+3y=12\\4(0)+3(0)=12\\0=12$

Which is an absurd. Therefore, $H$ doesn't contain the origin (and $H$ is a line in $IR^{2}$ ). Finally, it can't be a vector space of $V=IR^{2}$

8 0

3 years ago

Solve for a -8 = a(2+5)^2 +41 A. -1 B. 1 C. -2 D. 2

mario62 [17]

Answer:A

Step-by-step explanation:

-8=a(2+5)^2 + 41

-8=a x 7^2 + 41

-8=a x 7 x 7 +41

-8=49a+41

Collect like terms

-8-41=49a

-49=49a

Divide both sides by 49

-49/49=49a/49

-1=a

a=-1

5 0

3 years ago