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mojhsa [17]
3 years ago
9

Sin(-x)= -cos x for all values of x. True or false

Mathematics
2 answers:
Rudik [331]3 years ago
7 0
<h2>Answer:</h2>

The given expression :

        \sin (-x)=-\cos x is a false expression i.e. it is not true for all the values of x.

<h2>Step-by-step explanation:</h2>

We are asked to check whether the trignometric expression is true for all the values of x or not.

The expression is given by:

\sin (-x)=-\cos (x)

We consider x=0

Then on taking left hand side of the expression we have:

\sin (-0)\\\\i.e.\\\\\sin (0)\\\\=0

and the right hand side of the expression is:

-\cos x\\\\i.e.\\\\-\cos 0\\\\i.e.\\\\-1

i.e. we have:

0=-1

which is false.

Hence the statement is not true for all the values of x.

kogti [31]3 years ago
5 0

Answer:

That's incorrect. The simplest way to show this is by evaluating the functions at a given point. Let's say x=0, then:

Sin(-x) = Sin(0) = 0

-cos x = -cos (0) = -1

Therefore, Sin(-x)≠-cos x.

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Let r = radius, h = height and l = slant height 

Lateral area = rlpi 

But l = sqrt(r^2 + h^2) 

Lateral area = r sqrt( r^2 + h^2) pi = 20 pi..................(1) 

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I hope my answer has come to your help. God bless and have a nice day ahead!
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