<em>Answer: h = 120 ft; w = 80 ft </em>
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<em>A = 9600 ft^2</em>
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<em>Step-by-step explanation: Let h and w be the dimensions of the playground. The area is given by:</em>
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<em>A = h*w (eq1)</em>
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<em>The total amount of fence used is:</em>
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<em>L = 2*h + 2*w + w (eq2) (an extra distance w beacuse of the division)</em>
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<em>Solving for w:</em>
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<em>w = L - 2/3*h = 480 - 2/3*h (eq3) Replacing this into the area eq:</em>
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<em>We derive this and equal zero to find its maximum:</em>
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<em> Solving for h:</em>
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<em>h = 120 ft. Replacing this into eq3:</em>
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<em>w = 80ft</em>
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<em>Therefore the maximum area is:</em>
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<em>A = 9600 ft^2</em>
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The balloon is in the air for 3sThe max height is 44mThe max height occurs at x=0
Answer:
b. x less-than StartFraction 10 Over 3 End fraction
