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Murljashka [212]
3 years ago
9

2x+y=1 and 2x+y=-3 in graphing,Substitution,and elemination

Mathematics
1 answer:
earnstyle [38]3 years ago
5 0
2x+y=1
-2x-y=3

0¥4

y=-2x+1
y=-2x-3

-2x+1=-2x-3

0¥4

The answer to the question is no solution
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HELP WITH THESE QUESTIONS PART 2.
polet [3.4K]

Answer: (a) IV (b) positive (c) \frac{\pi}{4} (d) C (e) \sqrt{2}

<u>Step-by-step explanation:</u>

a) \frac{15\pi}{4} - \frac{8\pi}{4} = \frac{7\pi}{4}, which is located in Quadrant IV <em>per the Unit Circle.  </em>

b) sec is \frac{1}{cos}. Cos is the x-coordinate.  The x-coordinate inQuadrant IV is positive.

c) the reference angle is the angle from \frac{7\pi}{4} to 2π = \frac{\pi}{4}

d) since the angle is below the x-axis and the reference angle is\frac{\pi}{4}, then the angle is equal to -sec(\frac{\pi}{4})

e) sec = \frac{1}{cos}   ⇒   sec \frac{7\pi}{4} = \frac{2}{\sqrt{2} } = \frac{2}{\sqrt{2} }(\frac{\sqrt{2}} {\sqrt{2}}) = \frac{2\sqrt{2} }{2} = \sqrt{2}

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Answer: (a) \frac{3\pi}{2} (b) (0, -1) (c) A (d) -1

<u>Step-by-step explanation:</u>

a) \frac{11\pi}{2} - \frac{4\pi}{2} = \frac{7\pi}{2} - \frac{11\pi}{2} = \frac{3\pi}{2}

b) \frac{3\pi}{2} is on the Unit Circle at (0, -1)

c) sin = \frac{opposite}{hypotenuse} which equals \frac{y}{r} on the Unit Circle.

d) sin is the y-coordinate. sin (\frac{3\pi}{2}) = -1

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3 years ago
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Answer:

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Step-by-step explanation:

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Ouch! That is hard but I can do it. First, find the area of the triangle. (for both is 60) Then find the area of the rectangle (base) which is 48. Then do the rectangles on the sides which are 72 each (for both is 144) Then add it all together and get 252 ft squared or cubed. 
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dmitriy555 [2]

Answer:

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Step-by-step explanation:

Rotate AB 180 degrees in the clockwise direction.

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A shopkeeper sold a dressing table for 7512.75 at a profit of 19*1/4% What was the cost price.​
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