<span>t+3/2 = 1/2 // - 1/2
t+3/2-(1/2) = 0
t+3/2-1/2 = 0
t+1 = 0 // - 1
t = -1</span>
Answer:
Value is x=8 and y=4
Step-by-step explanation:
Given : A right triangle 'A' hypotenuse length of x+4 and a leg of x,
and right triangle 'B' hypotenuse length of 3y and a leg length of y+4
To find : For what values of x and y are the triangles congruent by HL?
Solution :
Triangle A,
Hypotenuse: x+4
Leg: x
Triangle B,
Hypotenuse: 3y
Leg: y+4
Since the triangle A and B are congruent so, the sides of triangles are equal.
(Hypotenuse are equal) ..........[1]
and
(Legs are equal) ..........[2]
Solving the equation of system,
Put the value of x from [2] in [1],




Substitute y in [2],
Therefore, The value of x=8 and y=4
Verifying for the values of x and y:
Triangle A,
Hypotenuse: x+4=8+4=12
Leg: x=8
Triangle B,
Hypotenuse: 3y=3(4)=12
Leg: y+4=4+4=8
Both hypotenuses and both legs are equal hence they are congruent.
31/50
31 ÷ 50 = 0.62
0.62 x 100 = 62%
So the answer is 62%
Hope this helps I didn't know if the 7k was apart of the problem or a typo
Answer:Does this helpf(t) = 1400(1 + (0.1)/2))2t
Step-by-step explanation: