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borishaifa [10]
3 years ago
5

30PTS!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!1

Mathematics
1 answer:
Yuliya22 [10]3 years ago
4 0

1)

a)

P = 1500, r = 4% = 0.04, n = 5

A = 1500 (1+0.04)^5= 1824.98

He shall have $1824.98 in his account after 5 years

b)

Here P = 1500 , r = 4% = 0.04, n = 5 but simple interest

So

I=PRn= 1500(.04)(5)=300

Interest = $300

Amount in his account after 5 years = 1500 + 300 = $1800

c)

First one shall yield a better income and by 1824.98-1800 = $24.98

2)

a)

P= $2000, r = 8% = 0.08 so quaterly = 0.08/4 = 0.02, n = 1 year

A = P(1+r)^{4n}  =2000(1+0.02)^4 =2164.86

There shall be $2164.86 after 1 year

b)

P = 2000, r= 8%=0.08 and n = 1 for simple interest

I=PRn = 2000(0.08)(1)=160

Amount after 1 year shall be 2000 + 160= $2160

c)

First option is a better option.

The difference is 2164.86 - 2160 = $4.86

3)

a)

Bank A

P= 3200, r = 3.5%= 0.035, n = 3 years for simple interest

I =3200(0.035)(3)=336

Interest earned in Bank A = $336

b)

Bank B

P = 3200, r = 3.4% = 0.034, n= 3

A= P(1+r)^n=3200(1+0.034)^3=3537.62

Interest earned = 3537.62 - 3200 = $337.62

c)

Tyler must choose Bank B as it fetches greater interest

d)

The difference in interest = 337.62 - 336 = $1.62


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The expression 200 - 16t2 models the height in feet of an object that falls from the initial height of 200 feet t seconds after
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  1. We are given the equation
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Austin has two Marvel posters he wants to hang on the wall in his bedroom. The wall is 16.5 feet wide and each poster is 5 3/4 f
vekshin1

The expression for the distance is w=5/3 ft

Step-by-step explanation:

The wall has a width of 16.5 feet

A single poster has a width of 5 3/4 ft which is equal to 23/4 ft or 5.75 ft

For the two posters, the width occupied is ; 23/4 * 2 = 23/2 = 11.5 ft

Remaining width that will be unoccupied by the posters will be 16.5-11.5=5

A sketch of the wall with the two posters such that the edge of the wall is the same as the distance between the posters will show three un-covered spaces, from edge of wall to the first poster, then between the two posters, and lastly from the second poster to the other edge of the wall.

The un-covered 3 portions have an equal width, lets assume that they have a width of w ft

This means 3w will represent the uncovered width which equals to the unoccupied space of 5 ft

Form equation for the uncovered width as;

3w=5ft

w=5/3 ft ---------the distance from the edge of each poster to the nearest edge of wall.

Learn More

Perimeter of a wall : brainly.com/question/12692838

Keyword :posters, wall, edge, distance

#LearnwithBrainly

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