B is the right choice.
You move the point to two spaces right, making 19.28 (percent).
Hey!!
here is your answer >>>
1) 3x - 10 > 11
let's take this as 3x - 10 = 11
3x = 21
x = 7
So, The numbers of X are always more than 7
2) 9x + 2 < 5
9x + 2 = 5
9x = 3
x = 1÷2
The numbers of X are always less than 1 ÷ 2
3) 2x + 8 < 6
2x + 8 = 6
2x = 2
x = 1
The numbers of X are less than 1
4) 4x - 3 < 12
4x - 3 = 12
4x = 15
x = 15 ÷ 4
The numbers of X are less than 15 ÷ 4
5) 2 ( 9 + x ) > 20
2 ( 9 + x ) = 20
9 + x = 10
x = 1
The numbers of X are more than 1
We can solve the rest using this
Hope my answer helps!
an really easy website for this is MathPapa algebra calculator
The answer is 28.09 g. I hope this helped.
Answer:
- If the sum is 6, a small cone will be ordered.
- If the sum is 8 or 9, a medium cone will be ordered.
- If the sum is 11, a large cone will be ordered.
Step-by-step explanation:
The table below shows the possible outcomes from drawing two balls. We see the relative frequencies to be ...
6: 4
8: 2
9: 2
11: 4
To make a fair decision, we want the relative frequencies of the decision possibilities to be the same. If we combine sums 8 and 9 to one category (medium cone, for example), then 6, (8 or 9), and 11 will all have the same relative frequency: 4.
The appropriate "fair decision" choice is ...
6: small cone
8 or 9: medium cone
11: large cone