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Alexandra [31]
2 years ago
14

Amy is eight years older than twice her cousin Alicia’s age. The sum of their ages is less than 32. Let x represent Alicia's age

. Which inequality represents Alicia’s possible age? 0
0
0

0
Mathematics
1 answer:
Vladimir [108]2 years ago
7 0
Assume that the age of Alicia is x and that of Amy is y
Twice the age of Alicia = 27
Eight years older means we will add 8
Therefore, the statement "<span>Amy is eight years older than twice her cousin Alicia’s age" can be represented as follows:
y = 8 + 2x (equation)
The sum of their ages is less than 32 can be represented as:
x + y < 32 which can also be written as y < 32-x (inequality)
</span>
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X-intercept (__,__) <br> Y-intercept (__,__)
Irina-Kira [14]

Answer:

X intercept is (0,-250) and Y intercept is (0,100)

Step-by-step explanation:

You just look at where the line intercepts the x and y intercepts

7 0
2 years ago
The slope of EF¯¯¯¯¯ is −52.
9966 [12]

Based on the above, the segments that are perpendicular to EF are LM and NP.

<h3>Why is the segment are LM and NP perpendicular  to EF ?</h3>

Note that when two lines are perpendicular, we can say that;

M1 * M2 = -1 As M1 and M2 are known to be the slopes of the lines.

Therefore, when the the slope of EF is said to be −5/2, then  one can say that the slope of  the segment that is said to be  perpendicular to EF will have to be equal to m1*m2=-1, m2=-1/m1, m2=-1/(-5/2) or m2=2/5.

Scenario one:

JK , if J is at (3, −2) and K is at (5, −7)

To find the slope JK, then

m=(y2-y1)/x2-x1)

m=(-7+2)/(5-3)

m=-5/2

-5/2 is not equal to 2/5

Therefore,  JK is not perpendicular to EF

Scenario 2

Find GH , when G is at (6, 7) and H is at (4, 12)

To find the slope GH

m=(y2-y1)/x2-x1)

m=(12-7)/(4-6)

m=5/-2

m=-5/2

Since -5/2 is not equal to 2/5 then GH is not perpendicular to EF

Scenario 3:

Find LM , If L is at (1, 9) and M is at (6, 11)

To find the slope LM, then

m=(y2-y1)/x2-x1)

m=(11-9)/(6-1)

m=2/5

Since 2/5 is equal to 2/5

Then LM is perpendicular to EF

Scenario 4:

Find NP , if N is at (−3, 4) and P is at (−8, 2)

To find the slope NP, then

m=(y2-y1)/x2-x1)

m=(2-4)/(-8+3)

m=-2/-5

m=2/5

Since 2/5 is equal to 2/5.

Therefore,  NP is perpendicular to EF

Based on the above calculations, the segments that are perpendicular to EF are LM and NP.

See correct format of question written below

The slope of EF is −5/2 .

Which segments are perpendicular to EF?

Select all the right answers please

1. JK , where J is at (3, −2) and K is at (5, −7)

2. GH , where G is at (6, 7) and H is at (4, 12)

3. LM , where L is at (1, 9) and M is at (6, 11)

4. NP , where N is at (−3, 4) and P is at (−8, 2)

Learn more about segments from

brainly.com/question/10565562

#SPJ1

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2 years ago
Help with #1 so I can get the gist of it please?
Virty [35]

Answer:

so you graph at (0,2), and go up one, over two for every other point you graph.

Step-by-step explanation:

rise over run.

basically, the m is the slope, and b is the y intercept (where it intersects the y axis).

so when looking at how to graph the line based on 1/2 or any other number, I use rise/run, which is basically telling us tha we need to go up one and over 2 (1/2)

if that makes any sense, let me know if you have any further questions. you got this, youre doing your best!!

slope is the start of your endless pain.

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kati45 [8]

Answer:

1/8

Step-by-step explanation:

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