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Murrr4er [49]
3 years ago
14

Can somebody help with this ?

Mathematics
1 answer:
Igoryamba3 years ago
8 0
You have to calculate the median and which the numbers all
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Write an equation for the description
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Answer:

She needs $55 more dollars

Step-by-step explanation:

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What is the measure of the arc represented by the numbers 6 and 11 on a clock face?
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150; because 6-11 is almost 180, but it’s not quite there, so it’s a little less
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0.909 &gt; 0.91<br>true or false <br>I need an answer and fast​
NeTakaya

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false

Step-by-step explanation:

0.909 is less than not greater than

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Mark and don are planning to sell each of their marble collections at a garage sale. if don has 4 more than 5 times the number o
natita [175]

Mark and Don have to sell 11 and 59 marbles respectively.

<em><u>Explanation</u></em>

Lets assume, the number of marbles Mark has  is x

As, Don has 4 more than 5 times the number of marbles mark has, so the number of marbles Don has = 5x+ 4

Question says that the total number of marbles is 70. So, the equation will be...

x+(5x+4)= 70\\ \\ 6x+4= 70 \\ \\ 6x = 70-4\\ \\ 6x=66 \\ \\ x= \frac{66}{6}= 11

<em>So, the number of marbles Mark has = 11 </em>

<em>and the number of marbles Don has = (5*11)+4 = 55+4= 59</em>

6 0
3 years ago
In a particular course, it was determined that only 70% of the students attend class on Fridays. From past data it was noted tha
siniylev [52]

Answer: Probability that students who did not attend the class on Fridays given that they passed the course is 0.043.

Step-by-step explanation:

Since we have given that

Probability that students attend class on Fridays = 70% = 0.7

Probability that who went to class on Fridays would pass the course = 95% = 0.95

Probability that who did not go to class on Fridays would passed the course = 10% = 0.10

Let A be the event students passed the course.

Let E be the event that students attend the class on Fridays.

Let F be the event that students who did not attend the class on Fridays.

Here, P(E) = 0.70 and P(F) = 1-0.70 = 0.30

P(A|E) = 0.95,  P(A|F) = 0.10

We need to find the probability that they did not attend on Fridays.

We would use "Bayes theorem":

P(F\mid A)=\dfrac{P(F).P(A\mid F)}{P(E).P(A\mid E)+P(F).P(A\mid F)}\\\\P(F\mid A)=\dfrac{0.30\times 0.10}{0.70\times 0.95+0.30\times 0.10}\\\\P(F\mid A)=\dfrac{0.03}{0.695}=0.043

Hence, probability that students who did not attend the class on Fridays given that they passed the course is 0.043.

8 0
3 years ago
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