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Dmitriy789 [7]
2 years ago
14

Growth and decay help me asap!

Mathematics
1 answer:
TEA [102]2 years ago
3 0

Answer:

growth, decay, growth, decay, decay

Step-by-step explanation:

If you raise 1 to any positive power you get 1.

If you raise a number greater than 1 to any positive power, you get more than 1. For example, 1.5^2 = 2.25, and 2.25 > 1.

If you raise a number between 0 and 1 to a positive power, you get a number that is less than 1. For example, 0.5^2 = 0.25.

Now look at each example. If the quantity raised to a power is greater than 1, it will give an answer greater than 1, so it is exponential growth.

If the quantity raised to a power is between 0 and 1, the result is less than 1, and it is exponential decay.

A. 1.3^t

1.3 > 1; this is growth.

B. 0.95^t

0.95 is between 0 and 1, so this is decay.

C. 1.03^t

1.03 > 1; this is growth

D. 0.73^t

0.73 is between 0 and 1, so this is decay.

E. 0.25^t

0.25 is between 0 and 1, so this is decay.

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The graph of a linear function is shown<br> below. What is the domain of the<br> function?
Viktor [21]

Answer:

{ x | -3 <= x < +1 }

Step-by-step explanation:

We note that the graph occupies from x=-3 to x=+1, while -3 is a value included (endpoint is solid), and +1 is excluded (endpoint hollow).

Thus the domain is { x | -3 <= x < +1 }

5 0
3 years ago
Math work help wanted
Sidana [21]

Answer:

\frac{31}{20}\pi

Step-by-step explanation:

The circumference of circle G is 2pi, which means that HJ is equal to 81/360*2pi = 9pi/20, which means that RJ is equal to 18pi/20-9pi/20 = 9pi/20. Therefore, RHJ is equal to the circumference of the area minus RJ, which is equal to 40pi/20 - 9pi/20 = 31pi/20

I hope this helps

3 0
2 years ago
Let f(x) =x+5 and g(x)=x^2-3 then f(g(x)) =?
guajiro [1.7K]

Answer:

Option (a) is true.

Step-by-step explanation:

Given the function

f(x)=x+5

g\left(x\right)=x^2-3

(f∘g)(x) = f(g(x)) = f(x²-3) = (x²-3)+5

                                      = x² + 2

Thus,

f(g(x)) = x² + 2

Therefore, option (a) is true.

6 0
2 years ago
A (0, 2) and B (6,6) are points on the straight line ABCD.
elena-14-01-66 [18.8K]

Answer:

(18, 14)

Step-by-step explanation:

We know that C and D lie on the line AB and BC = CD = AB. Then we need to use the distance formula and equation of the line AB to find the other two coordinates.

The distance formula states that the distance between two points (x_1,y_1) and (x_2,y_2), the distance is denoted by: \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}. Let's find the distance between A and B:

d = \sqrt{(6-0)^2+(6-2)^2}=\sqrt{6^2+4^2} =\sqrt{36+16} =\sqrt{52} =2\sqrt{13}

Now say the coordinates of D are (a, b). Then the distance between D and B will be twice of 2√13, which is 4√13:

4√13 = \sqrt{(6-a)^2+(6-b)^2}

Square both sides:

208 = (6 - a)² + (6 - b)²

Let's also find the equation of the line AB. The y-intercept we know is 2, so in y = mx + b, b = 2. The slope is (6 - 2) / (6 - 0) = 4/6 = 2/3. So the equation of the line is: y = (2/3)x + 2. Since (a, b) lines on this line, we can put in a for x and b for y: b = (2/3)a + 2. Substitute this expression in for b in the previous equation:

208 = (6 - a)² + (6 - b)²

208 = (6 - a)² + (6 - (2/3a + 2))² = (6 - a)² + (-2/3a + 4)²

208 = a² - 12a + 36 + 4/9a² - 16/3a + 16 = 13/9a² - 52/3a + 52

0 = 13/9a² - 52/3a - 156

13a² - 156a - 1404 = 0

a² - 12a - 108 = 0

(a + 6)(a - 18) = 0

a = -6 or a = 18

We know a can't be negative so a = 18. Plug this back in to find b:

b = 2/3a + 2 = (2/3) * 18 + 2 = 12 + 2 = 14

So point D has coordinates (18, 14).

8 0
3 years ago
Read 2 more answers
Helpppp :,[ also stay safe and have a great day!!!!!!!!!!!!!!!!!!!!!!1111
serious [3.7K]

Answer:

35÷7=5

Step-by-step explanation:

we have 7 small boxes in an oval and there are 5 ovals

All the boxes add up to 35

4 0
3 years ago
Read 2 more answers
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