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stepan [7]
3 years ago
10

There are 30 boys and 35 girls that try out for a chorus. The choir director will select 10 girls and 10 boys from the children

trying out. How many ways are there for the choir director to make his selection?
Mathematics
1 answer:
harina [27]3 years ago
3 0

Answer:

5.52 * 10^15 ways

Step-by-step explanation:

Given that there are 30 boys and 35 girls. The director will select 10 girls and 10 boys,

We use combinations when the question is on the number of ways of selecting objects  and the order of selection is not to be counted. Therefore, for this selection, the number of ways

= ³⁰C₁₀ × ³⁵C₁₀

= \frac{30!}{(30-10)!10!} *\frac{35!}{(35-10)!10!}

= \frac{30!}{20!10!} *\frac{35!}{25!10!}

= 30045015 * 183,579,396

= 5.51565 * 10^15

≈ 5.52 * 10^15 ways

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Answer:

The probability of the stick's weight being 2.33 oz or greater is 0.0041 or 0.41%.

Step-by-step explanation:

Given:

Weight of a given sample (x) = 2.33 oz

Mean weight (μ) = 1.75 oz

Standard deviation (σ) = 0.22 oz

The distribution is normal distribution.

So, first, we will find the z-score of the distribution using the formula:

z=\frac{x-\mu}{\sigma}

Plug in the values and solve for 'z'. This gives,

z=\frac{2.33-1.75}{0.22}=2.64

So, the z-score of the distribution is 2.64.

Now, we need the probability P(x\geq 2.33 )=P(z\geq  2.64).

From the normal distribution table for z-score equal to 2.64, the value of the probability is 0.9959. This is the area to the left of the curve or less than z-score value.

But, we need area more than the z-score value. So, the area is:

P(z\geq  2.64)=1-0.9959=0.0041=0.41\%

Therefore, the probability of the stick's weight being 2.33 oz or greater is 0.0041 or 0.41%.

5 0
3 years ago
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Answer

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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8 0
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Read 2 more answers
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