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yulyashka [42]
3 years ago
5

Write the standard form of the line that contains a y-intercept of -3 and passes through the point (3, 0). Include your work in

your final answer. Type your answer in the box provided or use the upload option to submit your solution.
Mathematics
1 answer:
mina [271]3 years ago
6 0
We have two points, (3,0) and (0,-3).  So we can find the slope of the line:

m=(y2-y1)/(x2-x1)

m=(-3-0)/(0-3)

m=-3/-3

m=1  so far for the line y=mx+b we have:

y=x+b, b is the y intercept which we were told is -3 so

y=x-3

The above is called the slope-intercept form of a line, y=mx+b, the standard form of a line is ax+by=c, so we need to get both variables on one side of the equation..

y=x-3  subtract x from both sides

-x+y=-3

While the above may be acceptable to some, technically the coefficient of x should be expressed as a positive value, so we should divide the above "solution" by -1 to get:

x-y=3
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The circumference is 56.52 m

Step-by-step explanation:

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An icicle with a diameter of 15.5 centimeters at the top, tapers down in the shape of a cone with a length of
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Answer:

Step-by-step explanation:

Note: I will leave the answers as fraction and in terms of pi unless the question states rounding conditions to ensure maximum precision.

From the question, we can tell it is a inversed-cone (upside down)

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a) Given Diameter , d = 15.5cm and Length , h = 350cm,

we first find the radius.

r = \frac{d}{2} \\=\frac{15.5}{2} \\=7.75cm

We will now find the volume of the cone.

Volume of cone  \pi (7.75)^{2} \frac{350}{3} \\= \frac{168175\pi }{24}

We know the density of ice is 0.93 grams per 1cm^{3}

1cm^{3} =0.93g\\\frac{168175\pi }{24}  cm^{3} =0.93(\frac{168175\pi }{24} )\\= 20473 g(Nearest Gram)

b) After 1 hour, we know that the new radius = 7.75cm - 0.35cm = 7.4cm

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Now we will find the volume of this newly-shaped cone.

Volume of cone = \pi (7.4)^{2} \frac{335}{3} \\= \frac{91723\pi }{15} cm^{3}

Volume of cone being melted = New Volume - Original volume

= \frac{168175\pi }{24} -\frac{91723\pi }{15} \\= \frac{35697\pi }{40} cm^{3}

c) Lets take the bucket as a round cylinder.

Given radius of bucket, r = 12.5cm (Half of Diameter) and h , height = 30cm.

Volume of cylinder = \pi r^{2} h\\=\pi (12.5)^{2} (30)\\=\frac{9375\pi }{2} cm^{3}

To overflow the bucket, the volume of ice melted must be more than the bucket volume.

Volume of ice melted after 5 hours = 5(\frac{35697\pi }{40} )\\=\frac{35697\pi }{8} cm^{3}

See, from here of course you are unable to tell whether the bucket will overflow as all are in fractions, but fret not, we can just find the difference.

Volume of bucket - Volume of ice melted after 5 hours

= \frac{9375\pi }{2} -\frac{35697\pi }{8 } \\=\frac{1803\pi }{8}cm^{3}

from we can see the bucket can still hold more melted ice even after 5 hours therefore it will not overflow.

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