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3 years ago

StarWatch Camping Site

Mathematics

2 answers:

alexandr402 [8]3 years ago

7 0

Answer:

YES with £18 spare

2.3 × 4.2 = 9.66

9.66 > 10

£15 per night

10 has 2 lots of five so 2 days free

only paying for eight

6 × 2 = 12

12 × 8 = 96

15 × 8 = 120

120 + 96 = 216

13 × 2 = 26

26 × 9 = 234

216 < 234

234 - 216 = 18

=> YES

blondinia [14]3 years ago

6 0

Answer:

Step-by-step explanation:

We first begin by finding how much the total expenses will be;

£6 per person per night = £6 * 2persons * 10nights = £120

They also need to pay for 8 nights out of 10 for the ground surface of the tent pitch. Since their tent is 9.66m², it's less than 10m² so they get to pay £15 * 8 = £120. We calculate for only one tent because they're sharing.

Their total expenses are £120 + £120 = £240.

Now let's look at their savings;

£13 * 2 persons * 9 weeks = £234

They will not have enough money for their holiday because they are £6 short of the £240 funds required.

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Leona [35]

Answer:

The right answer is "0.70".

Step-by-step explanation:

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By using the Bayes' theorem, we get

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3 years ago

What sum will amount to rupees 4000 in 3 years at 6% p.a. compound interest

natali 33 [55]

Answer:

$\begin{gathered}{\Large{\textsf{\textbf{\underline{\underline{\color{purple}{Given:}}}}}}}\end{gathered}$

⇢ Principle = Rs.4000
⇢ Rate = 6%
⇢ Time = 3 year

$\begin{gathered}\end{gathered}$

$\begin{gathered}{\Large{\textsf{\textbf{\underline{\underline{\color{purple}{To Find:}}}}}}}\end{gathered}$

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$\begin{gathered}{\Large{\textsf{\textbf{\underline{\underline{\color{purple}{Using Formula:}}}}}}}\end{gathered}$

${\dag{\underline{\boxed{\sf{Amount ={P{\bigg(1 + \dfrac{R}{100}{\bigg)}^{T}}}}}}}}$

$\dag{\underline{\boxed{\sf{Compound \: Interest = Amount- Principle }}}}$

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${\bigstar \:{\underline{\pmb{\frak{\red{Firstly,Finding \: the \: Amount }}}}}}$

$\quad {:\implies{\sf{Amount = \bf{P{\bigg(1 + \dfrac{R}{100}{\bigg)}^{T}}}}}}$

Substituting the values

$\quad {:\implies{\sf{Amount = \bf{4000{\bigg(1 + \dfrac{6}{100}{\bigg)}^{3}}}}}}$

$\quad {:\implies{\sf{Amount = \bf{4000{\bigg(1 \times 100 + \dfrac{6}{100}{\bigg)}^{3}}}}}}$

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$\quad {:\implies{\sf{Amount = \bf{4000{\bigg( \dfrac{53}{50} \times \dfrac{53}{50} \times \dfrac{53}{50}{\bigg)}}}}}}$

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$\quad {:\implies{\sf{Amount = \bf{4000 \times \dfrac{148877}{125000}}}}}$

$\quad {:\implies{\sf{Amount = \bf{4{\cancel{000}} \times \dfrac{148877}{125{\cancel{000}}}}}}}$

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3 years ago

I need help Evaluate functions from their graph

andreev551 [17]

Answer:

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We look for where $x=7$ . The way you find the answer is first, find the point $(0, 7)$ . Draw a line straight up and down, and see where that line intersects the function. Those intersection points are your answer(there will always be only 1 for a function, but if a graph isn't a function, there might be more than 1).