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Sedbober [7]
3 years ago
6

How do you solve this ?

Mathematics
2 answers:
jeyben [28]3 years ago
6 0
Idk i think you multiply 45 x 11 but im not smart and im pretty sure i havent learned this yet so dont trust me lol
antoniya [11.8K]3 years ago
6 0
There are a dozen ways in order to solve this, however, the simplest would probably be an application of law of sines combined with definition of interior angles of triangles.

the sum of interior angles of a triangle is 180 degrees, you're given that one angle is 45 degrees and another is 90 degrees, thus the missing angle is 45 degrees

now, Law of Sines states,
\frac{sin A}{a} =\frac{sin B}{b} = \frac{ sin C}{c}

other methods of solving the missing sides would be using the definition of sine,cosine, and tangent

sin(\theta) = \frac{opposite}{hypothenuse}
cos(\theta) = \frac{adjacent}{hypothenuse}
tan(\theta) = \frac{opposite}{adjacent}








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Save Work out the size of angle AED.<br> b) Work out x
Mamont248 [21]

Answer:

x = 10°

Step-by-step explanation:

a). Since, opposite angles of a cyclic quadrilateral are supplementary angles"

   Therefore, in cyclic quadrilateral ABDE,

   m∠ABD + m∠AED = 180°

   110° + m∠AED = 180°

   m∠AED = 180° - 110°

                 = 70°

b). AD = ED [Given]

   m∠EAD = m∠AED [Since, opposite angles of equal sides are equal in measure]

   m∠EAD = m∠AED = 70°

   By triangle sum theorem in ΔABD,

   m∠BAD + m∠ABD + m∠ADB = 180°

   m∠BAD + 110° + 40° = 180°

   m∠BAD = 180 - 150

                 = 30°

    m∠AEB = m∠AED + m∠DAB [By angles addition postulate]

    m∠AEB = 70° + 30°          

                  = 100°

    By triangle sum theorem in the large triangle,

    x° + m∠AEB + m∠EAB = 180°

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8 0
2 years ago
Is 16x2 - 16x + 4 a perfect square?
Andrew [12]

Answer:

Yes

Step-by-step explanation:

Use the completing the square method:

16(x^2-x)+4

=16((x-1/2)^2 - (1/2)^2)+4

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=16((x-1/2)^2) - 16/4 + 4

=16(x-1/2)^2

=4^2(x-1/2)^2

The product of two square is itself a square.

5 0
3 years ago
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