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Juli2301 [7.4K]
3 years ago
10

At a certain company, the mentoring program and the community outreach program meet at the same time, so it is impossible for an

employee to do both. If the probability that an employee participates in the mentoring program is 0.51, and the probability that an employee participates in the outreach program is 0.21, what is the probability that an employee does the mentoring program or the community outreach program?
Mathematics
1 answer:
Sedbober [7]3 years ago
8 0

Answer:

0.72

Step-by-step explanation:

Let A be the event that an employee attends mentoring program and B the community outreach program.

Since they meet at the same time, so it is impossible for an employee to do both.

i.e. P(Aintersection B) =0

Given that

P(A) = 0.51\\P(B) = 0.21

the probability that an employee does the mentoring program or the community outreach program

=P(AUB) = P(A)+P(B)-P(AB)\\=0.51+0.21-0\\=0.72

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