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Trava [24]
3 years ago
8

Plzzzzzzz helllp failing

Mathematics
1 answer:
telo118 [61]3 years ago
7 0

Answer:

i belive a or c please tell me if i waz wroung

You might be interested in
6b^3 (2a+7b), how to solve it?
slamgirl [31]
<span>6b^3 (2a+7b)

</span>
<span><span>(<span>6b^3</span>)</span><span>(<span>2a+7b</span><span>)

</span></span></span>
<span><span><span>=(<span>6b^3</span>)</span><span>(2a)</span></span>+<span><span>(<span>6b^3</span>)</span><span>(7b)

</span></span></span>
<span><span>=12ab^3</span>+<span>42<span>b^4]



Answer:  </span></span></span>
<span><span><span>12a</span><span>b^3</span></span>+<span>42<span>b^4</span></span></span>    
6 0
3 years ago
2. The line that passes through the points (-6, p)
Kobotan [32]
Answer: -26=p


Explanation: The slope formula is m=(y2-y1)/(x2-x1).

Thus, we have 6=(2-p)/(-10-(-6)).

Combining the xs gives us 6=(2-p)/-4.

Multiplying both sides by -4 leaves us with -24=2-p.

We do -24-2 to isolate p and find that p=-26.
5 0
2 years ago
Please help me? step by step:) ty
Illusion [34]

Answer:

multiply 5 x 4 = 20

multiply the dimensions of the lighter square

after all the multiplying you subtract your answers and you should get the VERY final answer

*don't add because it's area; just multiply

4 0
3 years ago
Find+the+positive+value+for+α+if+the+radius+of+the+circle+3x^2+3y-6αx+12y-3α=0+is+4
Alik [6]

Answer:

\alpha=3

Step-by-step explanation:

<u>Equation of a Circle</u>

A circle of radius r and centered on the point (h,k) can be expressed by the equation

(x-h)^2+(y-k)^2=r^2

We are given the equation of a circle as

3x^2+3y^2-6\alpha x+12y-3\alpha=0

Note we have corrected it by adding the square to the y. Simplify by 3

x^2+y^2-2\alpha x+4y-\alpha=0

Complete squares and rearrange:

x^2-2\alpha x+y^2+4y=\alpha

x^2-2\alpha x+\alpha^2+y^2+4y+4=\alpha+\alpha^2+4

(x-\alpha)^2+(y+2)^2=r^2

We can see that, if r=4, then

\alpha+\alpha^2+4=16

Or, equivalently

\alpha^2+\alpha-12=0

There are two solutions for \alpha:

\alpha=-4,\ \alpha=3

Keeping the positive solution, as required:

\boxed{\alpha=3}

8 0
3 years ago
I am stuck between two
Marina86 [1]

Answer:

It's 14.

Step-by-step explanation:

Google. ;)

3 0
3 years ago
Read 2 more answers
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