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Talja [164]
3 years ago
9

Sunset, inc., has a book value of equity of $14,865. long-term debt is $8,675. net working capital, other than cash, is $2,315.

fixed assets are $20,660 and current liabilities are $1,865. how much cash does the company have?
Mathematics
1 answer:
juin [17]3 years ago
8 0
Balance sheet equation states that:

Assets, A = Liabilities, L + Equity, E => A=L+E

In the current case,
L = Long term debt + Current liabilities = $8,675+$1,865 = $10,540
E = $14,865

Therefore,
A = 14,865 +10,540 = $25,405

Now,
Current assets (excluding cash) = current liabilities+Net working capital, other than cash = $1,865+$2,315 = $4,180

Additionally,
A = Fixed assets+Current assets (excluding cash) + Cash

Therefore,
Cash = 25,405-20,660-4,180 =  $565
 
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Step 1: Subtract -12 from both sides.

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2x^2 + 14x + 12 = 0

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2(x + 1)(x + 6) = 0

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x + 1 = 0 or x + 6 = 0

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What is the area of this composite figure, in square centimeters? A triangle with base of 11 centimeters and height of 6 centime
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209

Step-by-step explanation:

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The measurenicnt of the circumference of a circle is found to be 56 centimeters. The possible error in measuring the circumferen
BartSMP [9]

Answer:

(a) Approximate the percent error in computing the area of the circle: 4.5%

(b) Estimate the maximum allowable percent error in measuring the circumference if the error in computing the area cannot exceed 3%: 0.6 cm

Step-by-step explanation:

(a)

First we need to calculate the radius from the circumference:

c=2\pi r\\r=\frac{c}{2\pi } \\c=8.9 cm

I leave only one decimal as we need to keep significative figures

Now we proceed to calculate the error for the radius:

\Delta r=\frac{dt}{dc} \Delta c\\\\\frac{dt}{dc} =    \frac{1}{2 \pi } \\\\\Delta r=\frac{1}{2 \pi } (1.2)\\\\\Delta r= 0.2 cm

r = 8.9 \pm 0.2 cm

Again only one decimal because the significative figures

Now that we have the radius, we can calculate the area and the error:

A=\pi r^{2}\\A=249 cm^{2}

Then we calculate the error:

\Delta A= (\frac{dA}{dr} ) \Delta r\\\\\Delta A= 2\pi r \Delta r\\\\\Delta A= 11.2 cm^{2}

A=249 \pm 11.2 cm^{2}

Now we proceed to calculate the percent error:

\%e =\frac{\Delta A}{A} *100\\\\\%e =\frac{11.2}{249} *100\\\\\%e =4.5\%

(b)

With the previous values and equations, now we set our error in 3%, so we just go back changing the values:

\%e =\frac{\Delta A}{A} *100\\\\3\%=\frac{\Delta A}{249} *100\\\\\Delta A =7.5 cm^{2}

Now we calculate the error for the radius:

\Delta r= \frac{\Delta A}{2 \pi r}\\\\\Delta r= \frac{7.5}{2 \pi 8.9}\\\\\Delta r= 0.1 cm

Now we proceed with the error for the circumference:

\Delta c= \frac{\Delta r}{\frac{1}{2\pi }} = 2\pi \Delta r\\\\\Delta c= 2\pi 0.1\\\\\Delta c= 0.6 cm

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