Answer=7:13
Kenny's Weight*6/7=Melvin's Weight
So, for example, if Melvin's weigh was 7...
Kenny's Weight*6/7=7
divide both sides by 6/7
Kenny Weight=6
So we can say that Melvin's weight to Kenny's weight is 7:6
The boys total weights would be...
7+6=13
So Melvin's weight over the total weight of the two boys is:
7:13
Answer:
83422.5 grass seeds
Step-by-step explanation:
Applying,
A = 1/2bh....................... Equation 1
Where A = Area of the Triangle, b = base, h = height.
But, from the diagram,
tanФ = 20/b
b = 20/tanФ.................. Equation 2
Substitute equation 2 into equation 1
A = 1/2(20/tanФ)(h)................ Equation 3
Given: h = 20 m, Ф = 40°
Substitute these values into equation 3
A = 1/2(20×20)/tan40°
A = 200/tan40°
A = 238.35 m²
If the seed company recommends planting approximately 350 grass seeds per square meter,
Therefore,
Number of grass seed need = (350×238.35)
Number of grass seed needed = 83422.5 grass seeds
X + 2y = 6
2y = -x + 6
y = -1/2 x + 3 so slope = -1/2
parallel lines has same slope = -1/2
perpendicular lines slope is opposite and reciprocal so slope = 2
if slope not equal either -1/2 or 2 then neither.
y = -1/2 x - 5 ....m= - 1/2.... parallel
-2x + y = -4
y = 2x - 4...m = 2 ....perpendicular
-x + 2y = 2
2y = x + 2
y = 1/2 x + 1 ...m = 1/2 ...neither
x + 2y = -2
2y = -x - 2
y = -1/2 x - 1 ...m = -1/2 .....parallel
hope it helps
Answer:
<h2>Hyy There !! </h2>
Step-by-step explanation:
<h3><u>Question Says :- </u></h3>
• The Area of a sector when r = 9/2 and
θ = 5pi/6 radians ? .
? pi / ?
<h3><u>Circular Area of a Sector</u></h3>
Problems involving area of a sector can be solved easily. One should just obtain two essential information from the circle of interest, the central angle measure θ and radius r For angle measures in radians, the area A is calculated as :-
<h3>A = 1/2r^2θ. </h3>
<h3>Hope this helps you !! </h3>
Answer:
B. X+6.4<9.9
Step-by-step explanation:
The sum of a number is represented by X. So X and 6.4 is X+6.4. Is less than 9.9, so <9.9. You get X+6.4<9.9.
