Answer:
The probability that sample mean differ the true greater than 2.1 will be 2.8070 %
Step-by-step explanation:
Given:
Sample mean =46 dollars
standard deviation=8
n=53
To Find :
Probability that sample mean would differ from true mean by greater than 2.1
Solution;
<em>This sample distribution mean problem,</em>
so for that
calculate Z- value
Z=(sample mean - true mean)/(standard deviation/Sqrt(n))
Z=-2.1/(8/Sqrt(53))
Z=-2.1*Sqrt(53)/8
Z=-1.91102
Now for P(X≥2.1)=P(Z≥-1.91102)
Using Z-table,
For Z=-1.91
P(X>2.1)=0.02807
Step-by-step explanation:
(1/12)^-2b x 12^-2b+2=12
12^-(-2b) x 12^-2b+2=12
12^2b+(-2b+12)=12
2b-2b+12=12
=1
Answer:
a. x < 55
Step-by-step explanation:
We know that the temperature in November was less than 55° every single day, we are then asked to find which inequality out of the four given shows the temperature in November.
To do so, take the most crucial information, "the temperature in November was less than 55° every single day." The words "less than" makes us know that we will be using the sign "<". Looking at the answers, we see only one that uses it, and that is a.
Therefore a is the correct answer.
Answer:
6.2%
Step-by-step explanation:
Credit rating is an evaluation of the credit risk of a borrower, that how often a person is going to repay their debt, by credit rating it predicts the ability of the debtor to payback.
Mike has credit rating = 720
Tyler has credit rating = 560
Both are approved for loan. Mike's Credit score is higher, which means he is a much safer debtor as compared to Tyler. Mike will be able to pay back much easily than Tyler. Therefore Mike interest rate is 3.2%
Interest rate of Tyler is higher as he is not that trusted and has low Credit rating. Tyler is approved for a loan that charged 3 percentage points higher because of his inferior credit rating so it interest on the loan will be
Interest = 3.2%+3% = 6.2%
Answer:
dy/dx = (x^2 - 3)^sin x [2x sin x/ (x^2 - 3) + cos x ln(x^2 - 3)]
Step-by-step explanation:
y = (x^2 - 3)^sinx
ln y = ln (x^2 - 3)^sinx
ln y = sin x * ln (x^2 - 3)
1/y * dy/dx = sin x * {1 / (x^2 - 3)} * 2x + ln(x^2 - 3) * cos x
1/y dy/dx = 2x sin x/ (x^2 - 3) + cos x ln(x^2 - 3)
dy/dx = [2x sin x/ (x^2 - 3) + cos x ln(x^2 - 3)] * y
dy/dx = (x^2 - 3)^sin x [2x sin x/ (x^2 - 3) + cos x ln(x^2 - 3)]
