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Anika [276]
3 years ago
9

A small artichoke contains about 9 milligrams of vitamin C. It also contains about 15​% of the recommended amount of vitamin C a

n average adult should get each day. About how many artichokes would an average adult have to eat in a day to get the necessary amount of vitamin​ C
Mathematics
1 answer:
Tasya [4]3 years ago
6 0

Answer:

Well well well.

Step-by-step explanation:

DONOVON

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What is the slope (rate of change) for the table?
kvv77 [185]

Answer:

d

Step-by-step explanation:

i did this one

3 0
2 years ago
Using the image above, if the density of the LEGO piece is 0.85 g/cm^3, what COULD be a possible measurement for the density of
grin007 [14]

The Lego is submerged under the oil and therefore, is more dense than the oil

The possible density of the oil is the option;

<u>0.79 g/cm³</u>

Reason:

Given:

The density of Lego = 0.85 g/cm³

Density of oil = Required

Solution:

The density of an object is the mass per unit volume it occupies

  • Density = \dfrac{Mass}{Volume}

Increase in density increases the mass a unit volume occupies, therefore, a

more dense object is heavier than a less dense object such that the less

dense object will float on a dense object

The oil is floating on the Lego, therefore, the Lego is more dense than the

oil, and we have;

  • Density of Lego > Density of oil

The density of Lego = 0.85 g/cm³

Therefore;

0.85 g/cm³ > Density of oil

From the given options, the option that has a density less than 0.85 g/cm³ is the the option 0.79 g/cm³

Therefore, the possible density of the oil is <u>0.79 g/cm³</u>

<u />

Learn more here:

brainly.com/question/12864420

6 0
2 years ago
How do you do this problem?? I'm very confused
Mamont248 [21]
You have to multiply by the complex conjugate so that you can clear the radical from the denominator. Once you do the multiplication simplify the radical. There's still a common factor in -54, -18, & 75 so divide all those by 3.

7 0
3 years ago
If 22% of a number is 154, then the
yulyashka [42]

Answer:

22% = 154

100%= ?

=100×154/22

= 700

Step-by-step explanation:

5 0
2 years ago
What is the distance to the earth’s horizon from point P?<br><br> Express your answer as a decimal
rewona [7]

Answer:

The distance to the earth's horizon from point P is 216.2198187 mi, appriximately 216.22 mi

Step-by-step explanation:

This is a right triangle:

Hypotenuse: c=3959 mi + 5.9 mi → c=3964.9 mi

Leg 1: a=x=?

Leg 2: b=3959 mi

Using the Pytagorean theorem:

a^2+b^2=c^2

Replacing the known values:

(x)^2+(3959 mi)^2=(3964.9 mi)^2

Solving for x: Squaring:

x^2+15,673,681 mi^2=15,720,432.01 mi^2

Subtracting 15,673,681 mi^2 both sides of the equation:

x^2+15,673,681 mi^2-15,673,681 mi^2=15,720,432.01 mi^2-15,673,681 mi^2

x^2=46,751.01 mi^2

Square root both sides of the equation:

sqrt(x^2)=sqrt(46,751.01 mi^2)

x=216.2198187 mi

x=216.22 mi

3 0
3 years ago
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