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DedPeter [7]
3 years ago
5

How to solve for y 6x+3y=9 and 3x+2y=9

Mathematics
1 answer:
AURORKA [14]3 years ago
7 0
You move y so that it’s by itself then add common variables (Comment if you want a more detailed explanation)
The answer would be
Y= -6/3x +3 (for the 1st equation)
Y= -3/2x +4.5 (for the 2nd equation)
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Step-by-step explanation:

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PLEASE ANSWER FAST IM FAILING MATH!!!
posledela

Answer:

Step-by-step explanation:

From the figure attached,

Point B has been dilated to form point B'.

B(3, 1) → B'(6, 2)

          → B'[(2 × 3), (2 × 1)]

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4 0
3 years ago
A bank loaned out $21,500 , part of it at the rate of 11% annual interest, and the rest at 10% annual interest. The total intere
Luda [366]

Answer:

The loaned amount at 11 % is $ 19,000

The loaned amount at 10 % is $ 2,500

Step-by-step explanation:

Given as :

The total loan amount = $21,500

The total interest earn = $2,340.00

The rate of interest are 11 %  and 10 %

Let The loan amount at 11 % rate = $P

and The loan amount at 10 % rate = $21,500 - $P

Let The loan took for 1 year

Now,<u> From Simple Interest method </u>

Simple Interest = \dfrac{\textrm Principal\times \textrm Rate\times \textrm Time}{100}

SI_1 = \dfrac{P_1\times R_1\times \textrm Time}{100}

Or, SI_1 = \dfrac{P\times 11\times \textrm 1}{100}

Similarly

SI_2 = \dfrac{21,500 - P\times 10\times \textrm 1}{100}

∵  SI_1 +  SI_2 =  $2,340

Or, \dfrac{P\times 11\times \textrm 1}{100} + \dfrac{21,500 - P\times 10\times \textrm 1}{100} = $2,340

Or, 11 P - 10 P + 215000 = 234000

Or, P = 234000 - 215000

∴ P = $ 19,000

And $21,500 - $ 19,000 = $ 2,500

Hence The loaned amount at 11 % is $ 19,000

And     The loaned amount at 10 % is $ 2,500    Answer

8 0
3 years ago
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