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3 years ago

What is 150 mm expressed in decimeters?

Mathematics

2 answers:

Harlamova29_29 [7]3 years ago

6 0

Answer:C

Step-by-step explanation:

Nikitich [7]3 years ago

5 0

If i'm correct its c 1.5.

It should go base deci centi then milli

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Amanda, placed 2 orders with an Internet clothing store. The first order was for 13 ties, 4 pairs of suspenders, and totaled $48

Archy [21]

13x+4y=487------>13x+4y=487----------->13x+4y=487
6x+2y=232-------->-2(6x+2y)=232*-2---->-12x-4y=-464

x=23----> 6(23)+2y=232------->138+2y=232----->2y=94--->y=47

x=ties y=suspenders

5 0

4 years ago

Two packages weigh 3.92 pounds and 2.8 pounds. How many times heavier Is the first package than the second?

avanturin [10]

3.92/2.8=1.4

Unless it’s reverse.

2.8/3.92=0.714285714285 and so on.

3 0

4 years ago

Let f(x)=x^2 and g(x)=(x-3)^2+7 match up the correct transormations that are needed to transform the graph of f(x) to the graph

pentagon [3]

The transformations are vertical translation 7 units up.horizontal translation 3 units to the left

We have given that the equations

let f(x)=x^2 and g(x)=(x-3)^2+7

We have to determine the correct transformation,

<h3>What is the vertical translation?</h3>

Vertically translating a graph is equivalent to shifting the base graph up or down in the direction of the y-axis. A graph is translated to k units vertically by moving each point on the graph k units vertically.

Notice that the addition of 2 units to the variable x in the exponent involves a horizontal shift to the left in 2 units.

Notice as well that subtraction of 4 units to the functional expression involves a vertical shift downwards in 4 units.

To learn more about the transformation visit:

brainly.com/question/2689696

#SPJ1

5 0

2 years ago

Motorola used the normal distribution to determine the probability of defects and the number of defects expected in a production

Ghella [55]

Answer:

a) 0.3174 = 31.74% probability of a defect. The number of defects for a 1,000-unit production run is 317.

b) 0.0026 = 0.26% probability of a defect. The expected number of defects for a 1,000-unit production run is 26.

c) Less variation means that the values are closer to the mean, and farther from the limits, which means that more pieces will be within specifications.

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Assume a production process produces items with a mean weight of 10 ounces.

This means that $\mu = 10$ .

Question a:

Process standard deviation of 0.15 means that $\sigma = 0.15$

Calculate the probability of a defect.

Less than 9.85 or more than 10.15. Since they are the same distance from the mean, these probabilities is the same, which means that we find 1 and multiply the result by 2.

Probability of less than 9.85.

pvalue of Z when X = 9.85. So

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{9.85 - 10}{0.15}$

$Z = -1$

$Z = -1$ has a pvalue of 0.1587

2*0.1587 = 0.3174

0.3174 = 31.74% probability of a defect.

Calculate the expected number of defects for a 1,000-unit production run.

Multiplication of 1000 by the probability of a defect.

1000*0.3174 = 317.4

Rounding to the nearest integer,

The number of defects for a 1,000-unit production run is 317.

Question b:

Now we have that $\sigma = 0.05$

Probability of a defect:

Same logic as question a.

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{9.85 - 10}{0.05}$

$Z = -3$

$Z = -3$ has a pvalue of 0.0013

2*0.0013 = 0.0026

0.0026 = 0.26% probability of a defect.

Expected number of defects:

1000*0.0026 = 26

The expected number of defects for a 1,000-unit production run is 26.

(c) What is the advantage of reducing process variation, thereby causing process control limits to be at a greater number of standard deviations from the mean?

Less variation means that the values are closer to the mean, and farther from the limits, which means that more pieces will be within specifications.

3 0

3 years ago

What is 27.38 rounded to the nearest wholenumber?

Mamont248 [21]

27 is the answer . you only round up 5 and greater

5 0

3 years ago