Answer:
3
Step-by-step explanation:
Answer:
The answer to your question is below
Step-by-step explanation:
Question 1
x = 5 Equation l
2x + y = 10 Equation ll
- Substitute Equation l in equation ll
2(5) + y = 10
y = 10 - 10
y = 0
- Solution (5, 0)
Question 2
x + 16y = 20 Equation l
x = 4y Equation ll
Substitute equation ll in equation l
4y + 16y = 20
20y = 20
y = 20/20
y = 1
-Find x
x = 4(1)
x = 4
-Solution
(4, 1)
Question 3
2x + 8y = 20 Equation l
x = 2 Equation ll
-Substitute equation ll in equation l
2(2) + 8y = 20
4 + 8y = 20
8y = 20 - 4
8y = 16
y = 16/8
y = 2
- Solution
(2, 2)
Hope this helps! Because when you would fill in the variables 0=0 which which make the expression too that they’d equal the same.
9514 1404 393
Answer:
Step-by-step explanation:
The extrema will be at the ends of the interval or at a critical point within the interval.
The derivative of the function is ...
f'(x) = 3x² -4x -4 = (x -2)(3x +2)
It is zero at x=-2/3 and at x=2. Only the latter critical point is in the interval. Since the leading coefficient of this cubic is positive, the right-most critical point is a local minimum. The coordinates of interest in this interval are ...
f(0) = 2
f(2) = ((2 -2)(2) -4)(2) +2 = -8 +2 = -6
f(3) = ((3 -2)(3) -4)(3) +2 = -3 +2 = -1
The absolute maximum on the interval is f(0) = 2.
The absolute minimum on the interval is f(2) = -6.
Answer:
i dont know the other questions but i do know the last one and the answer is rhombus.