Question

For which nonnegative value of x is the expression 5+x/25-x^2

Answer 1

Answer:

Step-by-step explanation:

$\frac{5+x}{25-x^2} >0\\=\frac{5+x}{(5+x)(5-x)} \\=\frac{1}{5-x} >0\\if~5-x>0\\or~5>x\\or x$