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4 years ago

Billyana can read 1/2 a page every 2/5 minute.how much does billiyana read in 1 minute?

Mathematics

1 answer:

rusak2 [61]4 years ago

7 0

1 1/4 of a page in 1 minute Billy can read

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how do you solve -2.8k-4.31=-15.79 or 1.9m-3=-12.31 or 2.1a+1.4=-14.245 or 3.8n-4.8=-21.9 ?

Effectus [21]

Consider posting each question separately, please.

Given <span>-2.8k-4.31=-15.79 :

1) Isolate the "k" term on the left by adding 4.31 to both sides of this equation.
2) Simplify the right side.
3) Divide both sides by -2.8 and you'll have the answer: k = ?</span>

5 0

3 years ago

Explain how you can use compatible numbers to estimate the whole-number quotient of 925÷29.

alukav5142 [94]

Answer:

below

Step-by-step explanation:

Round 925 to 900

Round 29 to 30

900/30

= 30

Answer to 925/29:

31.89

7 0

3 years ago

Bryce measured the circumference of a tree trunk. Its circumference was 91 ft. What was the approximate diameter, rounded to the

iren2701 [21]

Answer: 29 feet.

Step-by-step explanation: The formula for the circumference of a circle is C = π d. In order to calculate the diameter of the tree we will use the same formula and solve for d.

91 = 3.14 x d

In order to solve for d you need to divide both sides for 3.14:

D = 28.98, rounded to the nearest foot is 29 feet.

5 0

3 years ago

If the area of traingle TQR is 60 cm square,what is the area of the parallelogram PQRS?<br>

Stolb23 [73]

Answer:

pls mark me brainlist .......my question was the same but no one ans I don't know

8 0

2 years ago

Given that <img src="https://tex.z-dn.net/?f=I_0%20%3D%2010%5E-12" id="TexFormula1" title="I_0 = 10^-12" alt="I_0 = 10^-12" alig

Alex Ar [27]

The intensity of sound which the decibel level of the sound measures 156 is 3.981 × 10³ W/m²

Decibel level, dB = 10log₁₀(I/I₀) where dB = decibel level = 156, I = intensity at 156 dB and I₀ = 10⁻¹² W/m².

Since we require I, making I subject of the formula, we have

dB/10 = log₁₀(I/I₀)

$\frac{I}{I_{0} } = 10^{\frac{dB}{10} } \\I = I_{0} 10^{\frac{dB}{10} }$

Substituting the values of the variables into the equation, we have

$I = I_{0} 10^{\frac{dB}{10} }\\I = 10^{-12} 10^{\frac{156}{10} }\\I = 10^{-12} 10^{15.6}\\I = 10^{15.6-12} \\I = 10^{3.6} W/m^{2}$

I = 3981.072W/m²

I = 3.981 × 10³ W/m²

So, the intensity of sound which the decibel level of the sound measures 156 is 3.981 × 10³ W/m²

Learn more about intensity of sound here:

brainly.com/question/4431819

3 0

3 years ago