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kondor19780726 [428]
2 years ago
10

One and three fourths subtracted from seven tenths

Mathematics
1 answer:
Brut [27]2 years ago
3 0
First convert both numbers into improper fractions. Then find the least (not greatest, photo is incorrect) common denominator and multiple by how much depending on your fraction. After that subtract and simplify needed.

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The radius of a cylinder is 5" and the lateral area is 70 pi sq. In. Find the length in altitude
aev [14]
We are to solve for the value of the altitude of the given cylinder which has a radius of 5 feet and a lateral area of 70pi ft². To solve this we should recall that the formula in solving the lateral area of a cylinder is Lateral Area = 2pi*r*h. The solution is shown below:
r is equal to 5 ft
lateral area = 70pi
Solving for h, we have:
70pi = 2pi*5*h
70pi / 2pi = 5h
35 = 5h
divide both sides by 5, we have:
35/5 = 5h/5
7 = h

The answer for the length of the altitude is 7 feet.
8 0
3 years ago
To make 6 apples pie, you need 2 pounds of apples. How many pounds of apples do you need to make 10 apple pies?
Bezzdna [24]
For every 6 apple pie, you need 2 pounds of apples.
So, how many pounds of apples do you need for 10 apple pies?
Well, first to figure out this question we first need to make a conversion factor.
I see in the fraction 6/3 we can simplify that to 2/1. Now we got our conversion factor.
We need to invert the fraction in order for the pie unit to cancel out.
1/2 * 10 = 5

You will need 5 pounds of apples to make 10 apple pies.

4 0
3 years ago
Read 2 more answers
For what value of x is the function g(x)=x/1-x NOT defined?
VMariaS [17]

The function is definately defined at x=0 but not x=1.

But its just one part of the coordinate (x,y).

If the value of y or f(x) is considered, you'll see that it is never possible to attain f(x)=0. In other terms (x,y)= (0,0) is not a defined point in the graph of the function because the graph doesnt pass through that point.

Now I hope you understood what I meant!

Conclusion- The above function is not defined at all points in the space having the abscissa or x=1 in the coordinate and also at ordinate or y=0 in the coordinate.nation:

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3 years ago
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andrew-mc [135]
Cot^2x - cot^2x cos^2x
= cot^2x - {(cot^2x)(cos^2x)}
= cot^2x { 1 - cos^2x }
= cot^2x { sin^2x }
= (cos^2x/sin^2x) { sin^2x }
= cos^2x
8 0
3 years ago
18, 7<br> The LCM of 18 and 7 is
Korvikt [17]

Answer:

126

Step-by-step explanation:

<em>Please</em><em> </em><em>mark</em><em> </em><em>me</em><em> </em><em>as</em><em> </em><em>brainlist</em>

4 0
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