Answer:
Step-by-step explanation:
Given that a basketball coach will select the members of a five-player team from among 9 players, including John and Peter.
Out of nine players five are chosen at random.
The team consists of John and Peter.
Hence we can sort 9 players as I group, John and Peter and II group 7 players.
Now the selection is 2 from I group and remaining 3 from II group.
Hence no of ways of selecting a team that includes both John and Peter=
=35
Total no of ways =
=126
=
=
the 2nd expression is the answer
Y=mx+b where m=-6, x=-2, and y=-3. Substituting these values in would result in -3=(-6)(-2)+b, which would simplify to -3=12+b, and further to b=-15. This would mean the y intercept is equal to -15, or (0,-15). To check, (-6)*(-2)-15 is in fact equal to -3, thus allowing easy identification of a graph, which will cross the y axis at -15 and decrease in y-value by 6 with every increase in x-value.